just put it over each other or search it up. that’s what i do
Let,
12x + 15y =34--------(1)
-6x + 5y =3-------(2)
(2) x 2 = -12x + 10y =6-------(3)
(3) + (1)
20y =40
y= 2
substitute y=2 into (1)
12x + 15(2) =34
12x =4
x= 1/3
<span>
<u><em>Answer:</em></u>The first group would have <u>12 cans</u>
The second group would have <u>16 cans</u>
<u><em>Explanation:</em></u>We know that the total number of cans in 28 and that the ratio between the two groups is 3:4
<u>This means that:</u>
If the first group has 3x cans, then the second group would have 4x cans.
<u>Now, we would solve for x:</u>
3x + 4x = 28
7x = 28
x = </span>

<span>
x = 4 cans
<u><em>Therefore:</em></u>
The first group would have 3x = 3(4) = 12 cans
The second group would have 4x = 4(4) = 16 cans
Hope this helps :)</span>