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2 years ago

What is the second derivative of 3secx?

Mathematics

1 answer:

7nadin3 [17]2 years ago

3 0

Hope this helps you.

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Let C(x) be the cost to produce x batches of widgets, and let R(x) be the revenue in thousands of dollars. R(x) = − x² + 6x, C

Musya8 [376]

Answer:

Step-by-step explanation:

Let C(x) be the cost to produce x batches of widgets, and let R(x) be the revenue in thousands of dollars.

$R(x) = -x^2 + 6x,\\ C(x) = x + 4.$

Profit function = Revenue - cost

So we get profit function by subtracting C(x) from R(x) using algebraic method of subtraction.

Profit function of x

= $Pr(x) = R(x) -C(x)\\= -x^2+6x-x-4\\=-x^2+5x-4$

7 0

2 years ago

Charles is planning his son’s birthday party and has a budget of $100. The Go Cart Corral charges $8 per child. How many childre

Montano1993 [528]

<h3>12 children</h3>

because

12 × 8 = 96

hope that helps :)

5 0

2 years ago

The polygons in each pair are similar.Find the missing side length

tatuchka [14]

I am gonna assume the answer is 8.If not another 4 i wish you could see the whole picture

6 0

2 years ago

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Solve the system of linear equations using elimination.

N76 [4]

Answer:

C (-2,1)

Step-by-step explanation:

−2x − y = 3 (1)

−9x − y = 17 (2)

(1) y = -2x - 3

(2) y = -9x - 17

-2x - 3 = -9x - 17

7x = -14

x = -2

y = -2(-2) - 3

y = 4 - 3

y = 1

8 0

3 years ago

Show work and explain with formulas.

Juli2301 [7.4K]

20 Answer: a₁ = 4

<u>Step-by-step explanation:</u>

$a_n=324,\ r=3,\ n=5\\\\a_n=a_1 \cdot r^{n-1}\\\\324=a_1\cdot 3^{5-1}\\\\\dfrac{324}{3^4}=a_1\\\\\dfrac{324}{81}=a_1\\\\\large\boxed{4}=a_1$

21 Answer: n = 13

<u>Step-by-step explanation:</u>

$a_n=\dfrac{1}{64},\ a_1=64,\ r=\dfrac{1}{2}\\\\a_n=a_1 \cdot r^{n-1}\\\\\dfrac{1}{64}=64\cdot \bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{64\cdot 64}=\bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{2^6\cdot 2^6}=\dfrac{1}{2^{n-1}}\\\\6+6=n-1\\\\\large\boxed{13}=n$

22 Answer: n = 5

<u>Step-by-step explanation:</u>

$a_n=48,\ a_1=1875\ r=\dfrac{2}{5}\\\\a_n=a_1 \cdot r^{n-1}\\\\48=1875\cdot \bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{48}{1875}=\bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{16}{625}=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\\bigg(\dfrac{2}{5}\bigg)^4=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\4=n-1\\\\\large\boxed{5}=n$

6 0

2 years ago

Read 2 more answers