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3 years ago

6

PLEASE HELP RIGHT AWAY

1 answer:

Angelina_Jolie [31]3 years ago

4 0

Answer:

12 flips

Step-by-step explanation:

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i haven't submitted a single assignment for this class since winter break bc i didn't realize she was assigning things on goform

rosijanka [135]

Answer and Step-by-step explanation:

<u>Trigonometric Function (These only work for right triangles):</u>

SOH-CAH-TOA

S = Sine = sin

C = Cosine = cos

T = Tangent = tan

O = Opposite (side)

H = Hypotenuse (side)

A = Adjacent (side)

SOH = sin(angle) = $\frac{opposite}{hypotenuse}$

CAH = cos(angle) = $\frac{adjacent}{hypotenuse}$

TOA = tan(angle) = $\frac{opposite}{adjacent}$

1. sinQ (Q is the angle) = $\frac{14}{50} = \frac{7}{25} = 0.28$

Use Pythagorean Theorem to find side PQ. $14^{2} + PQ^{2}= 50^{2} \\PQ^{2} = 2304\\PQ = 48$

2. cosQ = $\frac{48}{50} = \frac{24}{25} = 0.96$

3. tanQ = $\frac{14}{48} = \frac{7}{24} = 0.29$

3 0

2 years ago

What is 12,430,000 in expanded form?

Nady [450]

10,000,000+2,000,000+400,000+30,000

3 0

3 years ago

Solve for x<br> Please help me with this

Maru [420]

Answer:

hope this helps you look it once.

7 0

2 years ago

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You have a gift card for your favorite clothing store for the amount of $60. You have found a shirt you want for $15. You don't

Zolol [24]

Let

x--------> the amount you have left to spend

y--------> the cost of a shirt you want

z------> the amount of the gift card

we know that

$x+y \leq z$ --------> equation $1$

$y=\$ 15$ --------> equation $2$

$z=\$ 60$ --------> equation $3$

Substitute the equation $2$ and equation $3 in the equation [tex] 1$ [/tex]

$x+y \leq z$

$x+15 \leq 60$

therefore

<u>the answer is the option</u>

x+15 is less than or equal to 60

7 0

3 years ago

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Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

NikAS [45]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ <em>factoring 96</em>

<em>since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$ </em>

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>using exponent rule - $(a^{b}) ^{c} = a^{bc}$ </em>

<em> $\sqrt{2^{5} } = 2^{5/2}$ </em>

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>doing some simple simplification and $4=2^{2}$ and 6=2*3</em>

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

<em>collecting the roots on one side and applying exponent rule</em>

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

<em>Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$ </em>

<em>7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$ </em>

<em>combining all powers of 2</em>

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

<em>Simplifying</em>

9. $2^{9} *3^{2}\sqrt{3}$

10. $512*9\sqrt{3}$

11. $4608\sqrt{3}$

3 0

3 years ago

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