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Gnesinka [82]
3 years ago
10

For which of the following reactions will a decrease in pressure shift the equilibrium to the left?

Chemistry
1 answer:
spin [16.1K]3 years ago
4 0

Answer: I just took the test, the answer is A.

Explanation:

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Identify the type of sugar corresponding to each name. Sucrose Lactose Fructose Starch Glucose
hammer [34]

Answer: Please see answers in explanation column

Explanation:

Name                Type of sugars

Sucrose               Disaccharide

Sucrose, also called table sugar with molecular formulae C12H22O11  is a disaccharide  composed of two monosaccharides ( 50%glucose + 50%  fructose.).

Lactose                 Disaccharide

 Lactose with molecular formula C12H22O11, found in milk is a disaccharide composed of two monosaccharides (galactose and glucose).

Fructose                 Monosaccharide  

Fructose with molecular formulae C6H12O6 is a natural sugar mostly found in fruits.

Starch                  Polysaccharide

Starch ,a complex carbohydrate with molecular formula  (C6H10O5)n,  is a Polysaccharide containing many  units of glucose joined together by 1,4 linkages. Sources of starch can be found in the parts of plants( roots, tubers etc).

Glucose                 monosaccharides

Glucose, is a simple sugar (monosaccharides) with the molecular formula C6H12O6.  It is found in parts of plants  as well as in humans and known as blood sugar because of its location in the bloodstream.

8 0
3 years ago
What is CdF^4 compound name
topjm [15]

Answer:

well it might be 1.)Cadmium Fluoride CdF2 150.4078

2.)Cadmium(II) Perfluorate Cd(FO4) 2278.403

3.)Cadmium Ferrocyanide Cd2Fe(CN) 6436.7714

Explanation:

3 0
3 years ago
How are elements and compounds alike
Ad libitum [116K]
Both elements and compounds are pure substances. While elements are not made of simpler substances, compounds are made up of two or more chemical elements that are chemically combined.
7 0
3 years ago
What volume of 12 M HCl solution is needed to make 2.5 L of 1.0 M HCI?
Jlenok [28]

Answer:

0.21 L of 12 M HCL

Explanation:

CV=CV

(12)(x)=(1.0)(2.5)

x=0.21

8 0
4 years ago
Permanganate ion reacts in basic solution with oxalate ion to form carbonate ion and solid manganese dioxide. Balance the skelet
saw5 [17]

Answer:

2MnO4^- (aq) + 3C2O4^2- (aq) + 2H2O (l) --> 2MnO2(s) +6CO3^2 -(aq) + 4H^+ (aq)

Explanation:

First, write the half equations for the reduction of MnO4^- and the oxidation of C2O4^2- respectively. Balance it.

Reduction requires H+ ions and e- and gives out water, vice versa for oxidation.

Reduction:

MnO4^- (aq) + 4H^+ (aq) + 3e- ---> MnO2(s) + 2H2O (l)

Oxidation:

C2O4^2- (aq) + 2H2O (l) ---> 2CO3^2 -(aq) + 4H^+ (aq) + 2e-

Balance the no. of electrons on both equations so that electrons can be eliminated. we can do so by multiplying the reduction eq by 2, and oxidation eq by 3.

2MnO4^- (aq) + 8H^+ (aq) + 6e- ---> 2MnO2(s) + 4H2O (l)

3C2O4^2- (aq) + 6H2O (l) ---> 6CO3^2 -(aq) + 12H^+ (aq) + 6e-

Now combine both equations and eliminate repeating H+ and H2O.

2MnO4^- (aq) + 8H^+ (aq) + 3C2O4^2- (aq) + 6H2O (l) --> 2MnO2(s) + 4H2O (l) +6CO3^2 -(aq) + 12H^+ (aq)

turns into:

2MnO4^- (aq) + 3C2O4^2- (aq) + 2H2O (l) --> 2MnO2(s) +6CO3^2 -(aq) + 4H^+ (aq)

5 0
4 years ago
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