Answer:
No, potassium chloride will not dissolve completely. Only 28.15 g of potassium chloride will get dissolved.
Explanation:
Amount od potassium chloride added to 50 g of boiling water = 250.0 g
The solubility of potassium chloride in boiling water is 56.3 g/100 g water.
Amount of potassium chloride soluble in 100 g of boiling water = 56.3 g
Amount of potassium chloride soluble in 1 g of boiling water =
Amount of potassium chloride soluble in 50.0 g of boiling water :
Amount of potassium chloride left undissolved = 250.0 g - 28.15 g = 221.85 g
28.15 g of potassium chloride will dissolve and remaining 221.85 g og potassium chloride will not.
The question is: To neutralize 20ml of 0.1M HCl solution, 10ml of NaOH solution of concentration x mol/l is required. What is the value of x?
Answer: The value of x is 0.2 M.
Explanation:
Given: = 20 mL,
= 0.1 M
= 10 mL,
= x
Formula used is as follows.
Thus, we can conclude that the value of x is 0.2 M.
Answer: It will take 11.775 seconds.
Explanation: As a sphere with a diameter of 0.1 mm, the area of an alveolus is
A = 4.π.r²
r for an alveolus would be: r = 0.00005m or r = 5.m
Finding the area:
A = 4.3.14.(5.)²
A = 3.14.m²
The concentration change is to be 90% of the final, so
c = 0.9.3.14.
c = 28.26.
The oxygen diffusivity is 2.4.m²/s, that means in 1 second 2.4.
of oxygen spread in one alveolus area. So:
1 second = 2.4.m²
t seconds = 28.26.m²
t =
t = 11.775s
For a concentration change at the center to be 90%, it will take 11.775s.