All categories

3 years ago

What is the value of x?: -5x - 16 = 8x - 3

Mathematics

2 answers:

kykrilka [37]3 years ago

7 0

Answer:

X=-1

hope this helps :)

marysya [2.9K]3 years ago

5 0

Answer:

x = -13/3 or -4 1/3 or - 4.333...333

Step-by-step explanation:

-5x - 16 = 8x - 3

-16 = 8x - 3 - 5x

-16 + 3 = 8x - 5x

-13 = 3x

x = -13/3 or -4 1/3 or - 4.333...333

... represents that it has infinite amount of 3's

You might be interested in

What are the slope and y-intercept of the graph of this equation?

schepotkina [342]

Answer:

slope = y = 1/2

y-intercept = b = -3

Step-by-step explanation:

slope intercept equation:

y = mx + b----->(equation 1)

m is slope

b is y-intercept

y = 1/2x - 3----->(equation 2)

Compare (equation 1) and (equation 1)

slope = y = 1/2

y-intercept = b = -3

3 0

3 years ago

What is the circumference if a circle is 3cm

alekssr [168]

Answer:

0.48 cm

Step-by-step explanation:

6 0

4 years ago

Solve 7x-2x(x+1)=6x+14<br><br> A) x=-12<br> B) x=12<br> C) x=-16<br> D) x=16

prisoha [69]

Answer:

x=-16 (answer : C

Step-by-step explanation:

hello:

put x=-16 in this equation : 7x-2(x+1)=6x+14

7(-16)-2(-16+1)=6(-16)+14

-112-2(-15) = -96+14

-112+30= -96+14

-82 = -82 .....true

3 0

3 years ago

Are the points on the boundary line part of the<br> solution set or not?

Dmitry [639]

Answer:

yes

Step-by-step explanation:

8 0

3 years ago

I'm blanking on how to do this, I learned it so long ago, any help would be greatly appreciated. More interested on how to do it

anyanavicka [17]

Answer:

$\dfrac{16 y^{22}}{x^{10}z^{10}}$

Step-by-step explanation:

Given expression is ,

$\sf\longrightarrow \bigg(\dfrac{2x^3y^{-5}z^8}{8x^{-2}y^6z^3}\bigg)^{-2}$

This would be simplified using the law of exponents , some of which I will use here are ,

$(an)^m = a^m n^m$
$\dfrac{a^m}{a^n}=a^{m-n}$

$a^m a^n = a^{m+n}$
$a^{-n} = \dfrac{1}{a^n}$

Using the above laws ,

$\sf \longrightarrow \bigg[ \dfrac{2}{8} \bigg(\dfrac{x^3}{x^{-2}}\bigg)\bigg(\dfrac{y^{-5}}{y^6}\bigg)\bigg(\dfrac{z^8}{z^3}\bigg) \bigg]^{-2}$

Using the second law mentioned above , we have,

$\sf \longrightarrow \bigg[ \dfrac{1}{4}(x^{3+2})(y^{-5-6})(z^{8-3})\bigg]^{-2}$

Simplify ,

$\sf \longrightarrow \bigg[\dfrac{1}{4} x^5y^{-11}z^5\bigg]^{-2}$

Using the first law mentioned above , we have,

$\sf \longrightarrow \bigg[ \dfrac{1}{4^{-2}} x^{5(-2)} y^{-11(-2)} z^{5(-2)}\bigg]$

Simplify,

$\sf \longrightarrow 4^2x^{-10}y^{22} z^{-10}$

Finally using the fourth law mentioned above , we have ,

$\sf \longrightarrow \boxed{\bf \dfrac{16 y^{22}}{x^{10}z^{10}}}$

<h3>Option K is the correct answer.</h3>

4 0

2 years ago