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marishachu [46]
3 years ago
5

The __________ completed the united states’ “manifest destiny.

Mathematics
2 answers:
hjlf3 years ago
3 0
Louisiana purchase it completed it because it bought a bunch of land that spread from coast to coast
shepuryov [24]3 years ago
3 0

Answer:

hi

Step-by-step explanation:

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A store owner was buying uniforms for his employees. If each of his stores needed 79 uniforms and he had 64 stores which express
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Answer:

C) 80x60

Step-by-step explanation:

You round up the numbers to do the expression (:

4 0
3 years ago
80cm as a fraction of 4 m
lidiya [134]

Answer: 80 cm as a fraction of 4 m is 1/5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Is b+b+b+c+c+c is a equivalent expression?<br> A. True <br> B. False
Rama09 [41]

Answer:

A. True

Step-by-step explanation:

......................................................................................

5 0
3 years ago
It says to do 81^3/4 and i don’t know how to simplify that
scoundrel [369]

\bf 81^{\frac{3}{4}}~~ \begin{cases} 81=&3\cdot 3\cdot 3\cdot 3\\ &3^4 \end{cases}\qquad \implies (3^4)^{\frac{3}{4}}\implies 3^{4\cdot \frac{3}{4}}\implies 3^1\implies 3

7 0
3 years ago
To solve a polynomial inequality, we factor the polynomial
Pavel [41]

Answer:

To solve a polynomial inequality, we factor the polynomial into irreducible factors and find all the real _zeros_ polynomial. Then we find the intervals determined by the real _zeros and use test points in each interval to find the_ sign of the polynomial on that interval.

If P(x) = x(x+2)(x-1)

And P(x) ≥ 0

We see that P(x) ≥ 0 on the intervals (-2, 0) and (1, ∞).

Step-by-step explanation:

The complete question is attached to this solution

To solve inequality of a polynomial, we first obtain the solutions of the polynomial. The solutions of the polynomial are called the zeros of the polynomial.

If P(x) = x(x+2)(x-1)

The solutions of this polynomial, that is the zeros of this polynomial are 0, -2 and 1.

To now solve the inequality that arises when

P(x) ≥ 0

We redraw the table and examine the intervals

The intervals to be examined as obtained from the zeros include (-∞, -2), (-2, 0), (0, 1) and (1, ∞)

Sign of | x<-2 | -2<x<0 | 0<x<1 | x>1

x               | -ve | -ve | +ve | +ve

(x + 2)       | -ve | +ve | +ve | +ve

(x - 1)         | -ve | -ve | -ve | +ve

x(x+2)(x-1) | -ve | +ve | -ve | +ve

The intervals that satisfy the polynomial inequality P(x) = x(x+2)(x-1) ≥ 0 include

(-2, 0) and (1, ∞)

Hope this Helps!!!

6 0
3 years ago
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