To find the area of this rectangle you multiply the length by the width, like so (x+2) x (2x+5) .
To find the perimeter of this rectangle you add all the sides using this equation,
(x+2)+(x+2)+(2x+5)+(2x+5) .
Step-by-step explanation:
![\sqrt[8]{ {x}^{2} {y}^{6} } \\ \\ = ( {x}^{2} {y}^{6} )^{ \frac{1}{8} } \\ \\ = {x}^{2 \times \frac{1}{8}} {y}^{6\times \frac{1}{8}} \\ \\ = x^{\frac{1}{4}} {y}^{3\times \frac{1}{4}} \\ \\ = x^{\frac{1}{4}} {y}^{\frac{3}{4}} \\ \\ = \sqrt[4]{x {y}^{3} } \\](https://tex.z-dn.net/?f=%20%5Csqrt%5B8%5D%7B%20%7Bx%7D%5E%7B2%7D%20%20%7By%7D%5E%7B6%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%28%20%7Bx%7D%5E%7B2%7D%20%7By%7D%5E%7B6%7D%20%20%29%5E%7B%20%5Cfrac%7B1%7D%7B8%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%7Bx%7D%5E%7B2%20%5Ctimes%20%5Cfrac%7B1%7D%7B8%7D%7D%20%7By%7D%5E%7B6%5Ctimes%20%5Cfrac%7B1%7D%7B8%7D%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20%7By%7D%5E%7B3%5Ctimes%20%5Cfrac%7B1%7D%7B4%7D%7D%20%20%5C%5C%20%20%5C%5C%20%20%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%20%7By%7D%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%20%20%5C%5C%20%20%5C%5C%20%20%20%3D%20%20%5Csqrt%5B4%5D%7Bx%20%7By%7D%5E%7B3%7D%20%7D%20%20%5C%5C%20)
the greatest is 10 and the least is one but I don't know for sure but I don't know if that what you looking for
