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Flura [38]
3 years ago
6

What is the solution of this system of equations? x + 3y = 7 3x + 2y = 0

Mathematics
1 answer:
ololo11 [35]3 years ago
7 0

Answer:

X=-2, y=3

Step-by-step explanation:

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30 girls tried out for lacrosse team and 12 were selected and 40 boys tried out 16 were selecyed are the ratio of the number of
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Yes it is. When you simplify the girls ratio( 12:30 by 6)you'll get 2:5. When you simplify the boys ratio( 16:40 by 8)you'll get 2:5. So it is the same ratio.
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ABCD is a parallelogram. If AB= 3x -7 and CD = 5x - 19, find x.
kakasveta [241]

Answer:

x=6

Step-by-step explanation:

3x-7=5x-19

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8 0
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2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2=
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Answer:

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Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
SAT verbal scores are normally distributed with a mean of 433 and a standard deviation of 90. Use the Empirical Rule to determin
laila [671]

34% of the scores lie between 433 and 523.

Solution:

Given data:

Mean (μ) = 433

Standard deviation (σ) = 90

<u>Empirical rule to determine the percent:</u>

(1) About 68% of all the values lie within 1 standard deviation of the mean.

(2) About 95% of all the values lie within 2 standard deviations of the mean.

(3) About 99.7% of all the values lie within 3 standard deviations of the mean.

$Z(X)=\frac{x-\mu}{\sigma}

$Z(433)=\frac{433-\ 433}{90}=0

$Z(523)=\frac{523-\ 433}{90}=1

Z lies between o and 1.

P(433 < x < 523) = P(0 < Z < 1)

μ = 433 and μ + σ = 433 + 90 = 523

Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.

i. e. ((\mu-\sigma) \ \text{to} \ (\mu+\sigma))=68\%

Here μ to μ + σ = \frac{68\%}{2} =34\%

Hence 34% of the scores lie between 433 and 523.

8 0
3 years ago
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