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miv72 [106K]
3 years ago
7

Y = 4x^3– 20x^2+ 25x

Mathematics
1 answer:
posledela3 years ago
7 0

Answer:

0 2/5 By zeros

Step-by-step explanation:

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A factory produces pop-its at a constant rate. After 4 hours, 3,120 pop-its have been produced. What is the unit rate? (must sho
Viktor [21]

A

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Q.1
MrMuchimi
The question regards composite functions. A composite function is a function composed of more than one function. Sorry for saying the word function so many times there, it's just what it is...

The phrase f(g(x)) means 'perform g on an input x, then perform f on the result'. You can then see that there are many options for f(x) and g(x) here, in fact an infinite number of one were to be ridiculous about it.

However a sensible choice might be g(x) = x^2, and f(x) = 2/x + 9. Checking:

g(x) = x^2
f(g(x)) = 2/(x^2) + 9

That is the first question dealt with. Next up is Q2. It is relatively simple to show that these functions are inverses. If you start with a value x, apply a function and then apply the function's inverse, you should return to the same starting value x. To take a common example, within a certain domain, sin^-1(sin(x)) = x.

f(g(x)) = (sqrt(3+x))^2 - 3 = 3 + x - 3 = x

g(f(x)) = sqrt(x^2 - 3 + 3) = sqrt(x^2) = x

A final note is that this is only true for a certain domain, that is x <= 0. This is because y = x^2 is a many-to-one function, so unrestricted it does not have an inverse. Take the example to illustrate this:

If x = -2, f(x) = (-2)^2 - 3 = 4 - 3 = 1

Then g(f(x)) =sqrt(1 + 3) = sqrt(4) = 2 (principal value).

However the question isn't testing knowledge of that.

I hope this helps you :)
4 0
3 years ago
Need help ASAP! Please help with the slope to this question m= <br> B=
Inessa [10]

y=mx+b

therefore m = 1/2

and b = -6

7 0
3 years ago
The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. Determine the foll
Mrrafil [7]

Answer

given,

thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

X = U[0.95,1.05]           0.95≤ x ≤ 1.05

the cumulative distribution function of flange

F(x) = P{X≤ x}=\dfrac{x-0.95}{1.05-0.95}

                     =\dfrac{x-0.95}{0.1}

b) P(X>1.02)= 1 - P(X≤1.02)

                   = 1- \dfrac{1.02-0.95}{0.1}

                   = 0.3

c) The thickness greater than 0.96 exceeded by 90% of the flanges.

d) mean = \dfrac{0.95+1.05}{2}

              = 1

   variance = \dfrac{(1.05-0.95)^2}{12}

                  = 0.000833

4 0
4 years ago
Each shape is 1 whole. write a fraction greater than 1 for the parts that are shaded
sergij07 [2.7K]
What parts are shaded...you gotta help us out here bro...
6 0
4 years ago
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