Answer:
the energy required to break the bonds of reactant molecules
That is the best answer.
The answer is 9 out of 16 offspring or 56.25 percent.
It is known that the in dihybrid cross (a cross between two different traits), the phenotypic ratio between the offspring, which parents are heterozygous, is 9:3:3:1.
R is an allele for round seeds, r is the allele for wrinkled seeds.
Y is the allele for yellow seeds, and y is the allele for green seeds.
It can be assumed the following:
9 - individuals with both dominant traits (RRYY) - plants with round and yellow seeds.
3 - individuals with the first dominant trait and the second recessive trait (RRyy) - plants with round and green seeds.
3 - individuals with the first recessive trait and the first recessive trait (rrYY) - plants with wrinkled and yellow seeds.
<span>1 - individual with both recessive traits (rryy) - plants with wrinkled and green seeds.</span>
Explanation:
Ammonium hydroxide mostly acts as a reactant. Ammonium hydroxide is a colorless solution and exists only in solution form. It has a strong and pungent odor. It reacts with sulfuric acid and also many other strong acids. This reaction is exothermic which releases huge amount of heat or energy.
Ammonia water when in contact with volatile compounds, forms fumes. Ammonium hydroxide dissolves copper and zinc. It produces ammonia and nitroxides when heated to decomposition.
For every action there is an equal reaction perpendicular to the direction of the force is incorrect.