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Setler79 [48]
3 years ago
8

What is the area of the triangle? Use the formula: Area of a triangle = 1/2bh.How do you find the area of a triangle?

Mathematics
1 answer:
velikii [3]3 years ago
4 0

9514 1404 393

Answer:

  4 square inches

Step-by-step explanation:

The only triangle in the figure is 4 in wide and 2 in high. Using these values in the given formula, we find the area to be ...

  A = 1/2bh

  A = (1/2)(4 in)(2 in) = 4 in²

The area of the triangle is 4 square inches.

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Vera_Pavlovna [14]
Z=118 as vertically opposite angles are the same

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3 years ago
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a positive number is 5 times less than another positive number. Six times the lesser number plus 3 times the greater is 3. Find
IgorLugansk [536]
<h2>Greetings!</h2>

Answer:

One number is \frac{5}{7} and the other number is \frac{1}{7}

Step-by-step explanation:

Let x be the smaller number and y be the bigger number.

x = x

y = 5x

6x + 3y = 3

6x + (3 * 5x) = 3

6x + 15x = 3

(÷3)

2x + 5x = 1

7x = 1

x = \frac{1}{7}

6x + 3y = 3

6(\frac{1}{7}) + 3y = 3

\frac{6}{7} + 3y = 3

3y = 3 - \frac{6}{7}

3y = \frac{15}{7}

Divide both sides by 3 to get 1y:

y = \frac{5}{7}

So one number is \frac{5}{7} and the other number is \frac{1}{7}


<h2>Hope this helps!</h2>
5 0
3 years ago
How do i find volume of cone
lozanna [386]
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7 0
3 years ago
Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of
fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given :  the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Since, given the difference of the squares of the numbers is 5 that is (x^2-y^2)^2=5

And the product of the numbers is 6 that is xy=6

Using identity, we have,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Substitute, we have,

(x^2+y^2)^2=(5)^2+(2(6))^2

Simplify, we have,

(x^2+y^2)^2=25+144

(x^2+y^2)^2=169

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0
3 years ago
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ruslelena [56]
First shape: no parallel nor perpendicular

Second shape: parallel sides

Third shape: parallel sides

Fourth shape: perpendicular sides

Fifth: perpendicular sides

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8 0
3 years ago
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