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3 years ago

What is the area of the triangle? Use the formula: Area of a triangle = 1/2bh.How do you find the area of a triangle?

Mathematics

1 answer:

velikii [3]3 years ago

4 0

9514 1404 393

Answer:

4 square inches

Step-by-step explanation:

The only triangle in the figure is 4 in wide and 2 in high. Using these values in the given formula, we find the area to be ...

A = 1/2bh

A = (1/2)(4 in)(2 in) = 4 in²

The area of the triangle is 4 square inches.

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a positive number is 5 times less than another positive number. Six times the lesser number plus 3 times the greater is 3. Find

IgorLugansk [536]

<h2>Greetings!</h2>

Answer:

One number is $\frac{5}{7}$ and the other number is $\frac{1}{7}$

Step-by-step explanation:

Let x be the smaller number and y be the bigger number.

x = x

y = 5x

6x + 3y = 3

6x + (3 * 5x) = 3

6x + 15x = 3

(÷3)

2x + 5x = 1

7x = 1

x = $\frac{1}{7}$

6x + 3y = 3

6( $\frac{1}{7}$ ) + 3y = 3

$\frac{6}{7}$ + 3y = 3

3y = 3 - $\frac{6}{7}$

3y = $\frac{15}{7}$

Divide both sides by 3 to get 1y:

y = $\frac{5}{7}$

So one number is $\frac{5}{7}$ and the other number is $\frac{1}{7}$

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3 years ago

How do i find volume of cone

lozanna [386]

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3 years ago

Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

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3 years ago

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ruslelena [56]

First shape: no parallel nor perpendicular

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Fourth shape: perpendicular sides

Fifth: perpendicular sides

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