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3 years ago

What is the range of the function f(x) = |x − 1| − 2?

1 answer:

8 0

You obtain the graph of function $f(x)=|x-1|-2$ translating the graph of function $g(x)=|x|$ 1 unit left and 2 units down.

The range of the graph $g(x)=|x|$ is $[0,\infty]$ . When you make the needed translations you can see that the range of the function $f(x)$ is $[-2,\infty]$ .

Answer: $[-2,\infty]$ .

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Suppose two 1-6 number cubes are rolled. find the probability of each outcome. P(1 or 5)

stich3 [128]

Answer:

The probability of each outcome rolling two numbered cubes is 1/36 or 2.8% (Rounding to the next tenth)

Step-by-step explanation:

Probability of each outcome with one cube = Number of favorable events for each outcome/Total number of possible events

Replacing with the real values, we have:

Probability of each outcome with one cube = 1/6

Probability of each outcome with two cubes = 1/6 * 1/6 = 1/36

The probability of each outcome rolling two numbered cubes is 1/36 or 2.8% (Rounding to the next tenth)

3 0

4 years ago

Which is the equation of a line with a slope of -1/3 and a yintercept at (0, 1)?

posledela

Y = mx + b

m is -1/3

plug in your given values for x and y to find b

1 = (-1/3)(0) + b
1 = 0 + b
b = 1

make equation
y= (-1/3)x + 1

4 0

4 years ago

In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0

kolbaska11 [484]

Answer:

$Q_3 = 56.45$ --- The third quartile

$Var = 370.18$ -- Variance

Step-by-step explanation:

Given

$Q_1 = 30.8$ -- First quartile

$Q_2 = 48.5$ --- Median

$\bar x = 42$ --- Mean

$Skp = -0.38$ --- Coefficient of skewness

Solving (9): The third quartile $Q_3$

This is calculated from

$Skp = \frac{Q_1 + Q_3 - 2Q_2}{Q_3 - Q_1}$

So, we have:

$-0.38 = \frac{30.8 + Q_3- 2*48.5}{Q_3 - 30.8}$

Cross Multiply

$-0.38 (Q_3 - 30.8)= 30.8 + Q_3- 2*48.5$

Open bracket

$-0.38Q_3 + 11.704= 30.8 + Q_3- 97.0$

Collect like terms

$-0.38Q_3 -Q_3= 30.8 - 97.0- 11.704$

$-1.38Q_3= -77.904$

Divide both sides -1.38

$Q_3 = \frac{-77.904}{-1.38}$

$Q_3 = 56.45$ --- approximated

Solving (b): The variance

First, calculate the standard deviation from:

$3IQR = 4SD$

$IQR= Q_3 - Q_1$

So:

$3IQR = 4SD$

$3(Q_3 - Q_1) = 4SD$

Make SD the subject

$SD = \frac{3}{4}(Q_3 - Q_1)$

$SD = \frac{3}{4}(56.45 - 30.8)$

$SD = \frac{3}{4}*25.65$

$SD = \frac{3*25.65}{4}$

$SD = \frac{76.95}{4}$

$SD = 19.24$

So, the variance is:

$Var = SD^2$

$Var = 19.24^2$

$Var = 370.18$

5 0

3 years ago

The lengths of 2 sides of a triangle are 26 and 48. What is the range of possible side lengths for the 3rd side of the triangle?

iVinArrow [24]

Answer:

Step-by-step explanation:

If you add the 26 and 48 you get 74 and then you subtract 74 from 90 since your total needs to be 90 and get your answer of 16

3 0

3 years ago

Mario collected 3g seashells. Jasmine collected 10 more seashells than Mario. Write the number of seashells they collected toget

marin [14]

Mario = 3g

Jasmine = 10 more shells than Mario = 3g + 10

Hence, number of shells they collected together

= Mario + Jasmine = 3g + 3g + 10 = 6g + 10

7 0

3 years ago

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