Answer:
option D
Explanation:
There are four possible blood groups (A, B, AB, O) and six possible genotypes (AA, AO, BB, BO, AB, OO). Since the mother's bloodgroup is blood type A, then her genotype cannot be IAIB, ii(OO) or IBIB. Thus, we are left with the possible genotypes of IAIA (AA) and IAi (AO).
For her to produce a daughter with blood type O (OO), she has to be an heterozygote with the AO, contributing O so that the father assuming he is of blood type A or B negative (AO or BO) can contribute the second O.
For her to produce a son with type B negative which can only be of genotype BO since the mother is an AO (type A positive), he can only get the type B negative (BO) if his father is blood type B negative. this occurs with the mother contributing the O and the father contributing the B and the rhesus negative factor.
Answer:
C) <em>Hai Artisans</em>
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Answer:
they line the outer surfaces of organs and blood vessels
Explanation:
Answer:
D. The DNA in B is more positively charged than the DNA in A.
D. The DNA in B is more positively charged than the DNA in A.
Explanation:
Answer:
Genetic variation is always maintained.
Explanation:
One would think that the part of the population that is not favored in dry years would die and thus reduce the genetic variation but this is not likely to occur, otherwise all the population would die because some individuals would die in wet years and some in dry years. In reality they are able to survive in the transition from dry to humid years or viceversa. Actually, this variability that results from their genetic variability in their adaptability to changes in the climate is what keeps the population alive and able to thrive as time passes.
