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masha68 [24]
3 years ago
13

You have 236 feet of fence to work with. What the maximum area that can be fenced in?

Mathematics
1 answer:
alexandr1967 [171]3 years ago
4 0

Answer:

The maximum area is 4434.5 feet square.

Step-by-step explanation:

The fence maximum area it need to be fenced have to be shaped as circle. First we need to find radius of the circle:

2*\pi *r=236\\r=37.58

Maximum area will be fenced is:

S=\pi *r^{2} =3.14*37.58^2=4434.5

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Step-by-step explanation:

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2 years ago
What is the slope of the line that contains these points?
kati45 [8]

Answer:

m=-7

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from chart.</em>

Point (39, 36)

Point (40, 29)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{29-36}{40-39}
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8 0
3 years ago
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Distributions and Comparing Data Project
LenKa [72]

Answer:

1. The shape of the histogram created with MS Excel is approximately bell shaped and approximately evenly spread about the central (largest counts) values

The shape of the box plot created with MS Excel is approximately evenly distributed

2. The appropriate measure of central tendency for a bell shaped histogram is the mean and median, due to the approximately equal distribution about the highest frequency class

3. Part A

The 15 numbers between 1  and 20 generated by a random generator are;

1, 8, 8, 15, 4, 18, 11, 6, 17, 1, 18, 15, 10, 12, 11

The measure of center is the mean =  (1+8+8+15+4+18+11+6+17+1+18+15+10+12+11)/15 = 155/15 = 31/3

The measure of spread used is the variance, s² = 32.38

Where, \,s^2 =\dfrac{\sum \left (x_i-\bar x  \right )^{2} }{n - 1}

{\sum \left (x_i-\bar x  \right )^{2} } = 453.333

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s² = 453.\overline 3/(15 - 1) = 32.38

Part B

The measure of central tendency are the mean and the median because the size of the data (n = 15), is 75% of the population (N = 20) nd therefore the data is approximately normal and can be represented by the mean and the standard deviation

Step-by-step explanation:

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