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Keith_Richards [23]

3 years ago

6

Ross is shopping for mulch that costs $1.29 per cubic foot. During his first trip to the store, he bought 16.5 cubic feet. He ne

eds another 4.5 cubic feet to complete his landscaping project.

1 answer:

ankoles [38]3 years ago

5 0

Answer:

$27.09 in all

Step-by-step explanation:

$1.29 × 16.5 = $21.285

$1.29 × 4.5 = $5.805

$21.285 + $5.805 = $27.09

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To solve the equation for x by completing the square what equation is equivalent to x^2-x-2=0

GuDViN [60]

So to complete the square in
ax^2+bx+c=d form

make sure a=1
subtract c from both sides
take 1/2 of b and square it
add that to both sides
factor perfect square

1x^2-1x-2=0
a=1
move c to other side
add 2 to oth sides
x^2-1x=2
take 1/2 of b and square it
1/2 of -1=-1/2
squaer it
1/4
add that to both sides
x^2-1x+1/4=2+1/4
factor left side
(x-1/2)=2+1/4

first blank is 1/2

2+1/4=8/4+1/4=9/4

blanks are
1/2 and 9/4

3 0

3 years ago

A rectangle has a width of 12.5m and a length of 105m. What is the effect on the perimeter when the dimensions are multiplied by

vladimir1956 [14]

It is two times bigger

7 0

3 years ago

What is the nth term of 4, 6, 8, 10, 12

Troyanec [42]

$T_n = a_1 + (n - 1)d$

$a_1 = 4 , d = 2$

$T_n = 4 + 2(n - 1)$

$T_n = 4 + 2n - 2$

$T_n = 2n + 2$

--------------------------------------------
Answer: 2n + 2
--------------------------------------------

8 0

4 years ago

Please help idk any of this

AnnyKZ [126]

m<1=152

m<2=28

m<3=152

m<4=28

m<5=152

m<6=28

m<7=152

not completly sure but good luck

8 0

3 years ago

Assume that k and V0 are constant and are, respectively, 0.02, and 7. The parameter CA varies from an initial value CA0 = 100 to

julia-pushkina [17]

Answer:

V = 929.7

Step-by-step explanation:

Given the equation:

$\frac{dCA}{dV}$ = $\frac{-kCA}{V0}$

The integral of the above equation is:

$\int\limits {\frac{dCA}{dV} }$ = $\int\limits{\frac{-kCA}{V0} }$

Re-organizing the integrals:

$\int\limits {\frac{dCA}{CA} }$ = $\int\limits {\frac{-kdV}{V0} }$

Integrating:

ln(CA) - ln(CA0) = $\frac{-kV}{V0}$

Inputting the initial conditions of CA and the values of k and V0:

ln(7) - ln(100) = $\frac{-0.02V}{7}$

1.946 - 4.605 = -0.00286V

-2.659 = -0.00286V

=> V = $\frac{2.659}{0.00286}$

V = 929.720

Approximating to one decimal place,

V = 929.7

7 0

3 years ago