Solid paper costs 1.75 each
Printed paper costs 2.50 each
Given:
Ben = $43.50 (12 rolls solid paper and 9 rolls of
printed paper)
Joel = $51.50 (8 rolls solid paper and 15 rolls of
printed paper)
Let x = solid paper
Let y= printed paper
12x + 9y = 43.50
8x + 15y = 51.50
Find X:
8x + 15y = 51.50
8x = 51.50 - 15y
x= (51.50 - 15y)8
Substitute X:
12x + 9y = 43.50
12(51.50 - 15y)/8 + 9y = 43.50
(618 - 180y)/8 + 9y = 43.50
8 (618 - 180y)/8 + 8*9y = 43.50 * 8
618-180y + 72y =348
-108y = 348 - 618
-108y =-270
-108y/-108=-270/-108
Y= 2.50
x = (51.50 - 15y)/8
x = (51.50 - 15(2.5) /8
x= (51.50 - 37.50\8
X = 14/8
X = 1.75
To check: x = 1.75; y = 2.5
12x + 9y = 43.50
12(1.75) + 9(2.5) = 43.50
21 + 22.50 = 43.50
43.50 = 43.50
8x + 15y = 51.50
8(1.75) + 15(2.5) = 51.50
14 + 37.50 = 51.50
51.50 = 51.50
Hope that helps! Have a good day :)
I believe it’s 100 hopefully it helps
Problem A,B,C, and D can be solved using 3*6=18 or 6*3=18
Using the least common factor, it is found that:
- a) 60 packages should be bought.
- b) There will be 5 filled goody bags.
<h3>
Least Common Factor:</h3>
- The sizes of the packages are: 10, 6, 15 and 12.
- To fill each bag and have no left-overs, the number of packages is the <u>least common factor</u> of these amounts.
- The least common factor is found factoring the numbers into prime factors.
Item a:
10 - 6 - 15 - 12|2
5 - 3 - 15 - 6|2
5 - 3 - 15 - 3|3
5 - 1 - 5 - 1|5
1 - 1 - 1 - 1
Hence, lcf(10,6,15,2) = 2 x 2 x 3 x 5 = 60.
60 packages should be bought.
Item b:
Goody bags are in packages of 12, hence:
60/12 = 5.
There will be 5 filled goody bags.
To learn more about the least common factor, you can take a look at brainly.com/question/24873870
