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3 years ago

Prove that x=2 if 4^x=8x...where ^ stands for "to the power of".

1 answer:

4 0

In order to prove this, you simply plug in the number 2 everywhere you see X:

4^(2) = 8(2).

Simplify

16 = 16 √

Since this checks out, x is proven to be 2.

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What is 4 divided into 3 1/3

ipn [44]

Answer:

1 1/5

Step-by-step explanation:

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3 years ago

Find the standard form of the equation of the parabola with a focus at (0, -10) and a directrix at y = 10

Sophie [7]

Answer:

y=-1/40x^2 is the answer i just took the test

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2 years ago

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Answer:

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2 years ago

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What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16

kicyunya [14]

Answer:

$y=\pm i \sqrt{7}$

Step-by-step explanation:

Given equation is $\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

Factor denominators then solve by making denominators equal

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$y\left(y+4\right)-4\left(y-4\right)=9$

$y^2+4y-4y+16=9$

$y^2=9-16$

$y^2=-7$

take squar root of both sides

$y=\pm \sqrt{-7}$

$y=\pm i \sqrt{7}$

Hence final answer is $y=\pm i \sqrt{7}$ .

7 0

3 years ago

Given the system of inequalities:

STatiana [176]

Slope intercept form : y = mx + b

4x - 5y < 1
-5y < -4x + 1
y > 4/5x - 1/5 <== slope intercept form

y - x > 3
y > x + 3 <== slope intercept form

8 0

3 years ago

Read 2 more answers