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gladu [14]
3 years ago
8

License plates are made using 3 letters followed by 2 digits. How many plates can be made if repetition of letters and digits is

allowed?
A)1,757,600
B)11,881,376C)100,000
D)175,760
Mathematics
1 answer:
Helga [31]3 years ago
8 0

Answer:

26^3\times10^2 = 1757600

option B is correct

Step-by-step explanation:

We have 5 spaces in the license plate:

_ _ _ _ _

we have 26 available letters, and 10 available numbers.

starting with letters:

  • how many choices do i have to place the 1st letter? 26.

26 _ _ _ _

  • how many choices do i have to place the 2nd letter? 26 (since we're allowed to repeat letters)

26 26 _ _ _

  • how many choices do i have to place the 3rd letter? 26

26 26 26 _ _

we've used all the places for letters, (note: the exact position of the letters doesn't matter here, the first letter could've been placed anywhere in _ _ _ _ _, but the amount of possible choices for letters would always be 26).

let's move on to numbers.

  • how many choices do i have to place the 1st number? 10

26 26 26 10 _

  • how many choices do i have to place the 2nd number? 10

26 26 26 10 10

we've completed our number plate. Next we'll simply multiply all these numbers to get all the possible arrangements in which numbers and letters can be displayed on a license place.

26^3\times10^2 = 1757600

option B is correct

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Answer:

y= x squared.

Step-by-step explanation:

When graphed, the parabola only has an x-intercept at (0,0). Since a root is another word for an x-intercept, it only has one root.

I hope this helps, and I hope you have a good day.

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The weights of soy patties sold by Veggie Burgers Delight are normally distributed. A random sample of 15 patties yields a mean
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Answer:

t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549    

Step-by-step explanation:

Data given and notation  

\bar X=3.8 represent the sample mean

s=0.5 represent the sample standard deviation for the sample  

n=15 sample size  

\mu_o =4 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean weight is less than 4 ounces, the system of hypothesis would be:  

Null hypothesis:\mu \geq 68  

Alternative hypothesis:\mu < 4  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549    

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Step-by-step explanation:

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Step-by-step explanation:

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MrRa [10]

Answer:

x = 4

Step-by-step explanation:

110ₓ = 40₅    --------- change all to base ten.

<u>the system called binary</u>

1x²+1x ¹+0x⁰ = 45¹+0*5⁰

x² + x + 0 = 20

x² + x – 20 = 0

solve x using Quadratic equation

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x =  ------------------------------------

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