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Luda [366]
3 years ago
7

Classify the following as either an element, a compound, a homogeneous mixture, or a heterogeneous mixture.

Chemistry
2 answers:
julsineya [31]3 years ago
8 0

Answer:

Salt issolved in water: homogeneous mixture

muddy water : heterogeneous mixture

Sodium fluoride = compound

Silver = element

Explanation:

Step 1:

A heterogeneous mixture is a mixture in which the composition is not uniform throughout the mixture.

A homogeneous mixture is a mixture in which the composition is uniform throughout the mixture.

A chemical compound is a chemical substance consisting of two or more different chemically bonded chemical elements, with a fixed ratio determining the composition.

An element is a substance whose atoms all have the same number of protons: another way of saying this is that all of a particular element's atoms have the same atomic number. Elements cannot be broken down using chemical reactions.

Salt dissolved in water = Salt is soluble in water, which would give a homogeneous mixture

Muddy water = Muddy water, on the other hand is a heterogeneous mixture because mud can settle, leaving the mixture with much less mud at the top of the bucket than the bottom.

Sodium floride =  a compound made of 2 elements: Sodium and fluoride

Silver = An element, it can be found on the period table.

Masteriza [31]3 years ago
7 0
Sodium fluoride-compound
Silver- element
Salt dissolved in water- heterogeneous
Muddy water- homogeneous
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dolphi86 [110]

<u>Answer:</u> 4.999 moles of excess reactant will be left over.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       .....(1)

Given mass of aluminium carbide = 112 g

Molar mass of aluminium carbide = 143.96 g/mol

Putting values in equation 1:

\text{Moles of aluminium carbide}=\frac{112g}{143.96g/mol}=0.778mol

For the given chemical reaction:

2Al_4C_3(s)+12H_2O(l)\rightarrow 3CH_4(g)+4Al(OH)_3(s)

By the stoichiometry of the reaction:

2 moles of aluminium carbide reacts with 12 moles of water

So, 0.778 moles of aluminium carbide will react with = \frac{12}{2}\times 0.778=4.668 mol of water

Given mass of water = 174 g

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Putting values in equation 1:

\text{Moles of water}=\frac{174g}{18g/mol}=9.667mol

Moles of excess reactant (water) left = 9.667 - 4.668 = 4.999 moles

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8 0
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Answer:

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