The standard Gibbs energy of reaction, ÄG°, for the dissociation of phenol is 56.4 kJ mol-1 at 298 K. Calculate the pKa of pheno
1 answer:
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The symbol is for phosphorus having atomic number 15. That means it has
in its neutral state.
The given symbol has a -3 charge that means it has gained 3 electrons so, the number of electrons in the
is:
. The number of protons will remain same that is the number of protons = 15.
So, the ion has
that gives
charge on the
ion.
So, the answer is .
Hello!
The pressure of the Ideal Gas when the volume is 1,45 L and the temperature is 298 K is 1,82 atm.
To solve this problem we need to apply the Ideal Gas Law for the initial conditions and the final ones, clearing the equation for the number of moles (n) and the ideal gas constant (R) which remain constant:
Now we match n*R for the initial conditions (1) and the final ones (2), clearing the equation for P₂
Have a nice day!
The pressure of the Ideal Gas when the volume is 1,45 L and the temperature is 298 K is 1,82 atm.
To solve this problem we need to apply the Ideal Gas Law for the initial conditions and the final ones, clearing the equation for the number of moles (n) and the ideal gas constant (R) which remain constant:
Now we match n*R for the initial conditions (1) and the final ones (2), clearing the equation for P₂
Have a nice day!