Given that
Mass of water = 65.34 g
Amount of heat = mass of water * specific heat (temperature change
)
= 65.34 g * 4.184 J / g-C ( 21.75-18.43 )C
= 907.63 J
= 0.908 KJ
And
1 cal = 4.186798 J
907.63 J * 1 cal / 4.186798 J =216.78 cal
Or0.218 kcal
Answer:
C. BF3
Explanation:
The boron in BF3 is electron poor and has an empty orbital, so it can accept a pair of electrons, making it a Lewis acid.
(46.972* 69.472% + 48.961*21.667% + <span>49.954*8.8610%)/100% =
</span>= 46.972* 0.69472 + 48.961*0.21667 + 49.954*0.088610 =47.667 u
The remaining moles of C is 5.01 moles while the remaining moles of F₂ is 0.
<h3>
Reaction between Carbon and Fluorine </h3>
The reaction between carbon and Fluorine is given as;
C + 2F₂ -------> CF₄
1 : 2 1
from the reaction above,
2 moles of F₂ requires 1 mole of C
7.88 mole of F₂ will require: 7.88/2 = 3.94 moles of C and 3.94 moles of CF₄.
The remaining moles of C = 8.95 - 3.94 = 5.01 moles while the remaining moles of F₂ is 0.
Learn more about moles here: brainly.com/question/15356425
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