How many moles of carbon dioxide are released daily by a humming birds respiration?

In the copper – silver nitrate lab Copper medals and silver nitrate solution reacted to produce silver metal and copper (II) nit

Nataly [62]

Answer:

Percent Yield = 97.75 %

Explanation:

1 MOLE = It is equal to the molar mass of the substance

1 mole of Cu = 63.54 g (Molar Mass of Cu = 63.54 g/mole)

1 mole of AgNO3 = 170 g (Molar Mass of AgNO3 = 170 g/mol)

Given Mass of AgNO3 = 1.41 g

Given Mass of Cu = 2.93 g

Second step : Find the limiting Reagent (which is in less amount)

Balanced Chemical equation :

$Cu + 2AgNO_{3} \rightarrow Cu(NO_{3})_{2}+2Ag$

This means

1 mole of Cu will react with = 2 mole of AgNO3

63.54 g of Cu reacts with = 2 x 170 g of AgNO3

1 g of Cu reacts with = (2 x 170)/63.54 of AgNO3

$= \frac{170\times 2}{63.54}$

= 5.35 g of AgNO3

2.93 g should reacts with = 2.93 x 5.35 = 15.67 g of AgNO3

Available AgNO3 = 1.41 g

So , AgNO3 is less than required = limiting reagent

Now the reaction occur 1.41 g of AgNO3

Now, Limiting reagent will decide How much Silver(Ag) Metal will form

2 mole of AgNO3 will produce = 2 mole of Ag

1 mole of AgNO3 will produce = 1 mole of Ag

170 g AgNO3 will produce = 107.86 mole of Ag(Molar mass of Ag = 107.86)

1 g AgNO3 will produce =

$\frac{107.86}{170}$

1.41 g of AgNO3 will produce =

$\frac{107.86\times 1.41}{170}$

= 0.89 g

$Yield\ Percent = \frac{Actual\ Yield}{Theoritical\ Yield}\times 100$

Actual yield = 0.87 g

Theoritical yield = 0.89 g

$Yield\ Percent = \frac{0.87}{0.89}\times 100$

Percent Yield = 97.75 %

5 0

3 years ago

What would you use if you needed to determine the density of an object?

Monica [59]

What would you use if you needed to determine the density of an object?

Balance and Graduate Cylinder

Hope This Helps! \(★ω★)/

8 0

3 years ago

Ion Concentration 1. Which solution has the greatest [SO42-]: a) 0.075 M H2SO4 b) 0.15 M Na2SO4 c) 0.080 M Al2(SO4)3?

soldi70 [24.7K]

Answer:

c) 0.080 M Al₂(SO₄)₃

Explanation:

Ion [SO₄²⁻] concentration of each solution is:

a) 0.075 M H₂SO₄: [SO₄²⁻] = 0.075M. Because 1 mole of H₂SO₄ contains 1 mole of SO₄²⁻

b) 0.15 M Na₂SO₄: [SO₄²⁻] = 0.15M. Also, 1 mole of Na₂SO₄ contains 1 mole of SO₄²⁻

c) 0.080 M Al₂(SO₄)₃ [SO₄²⁻] = 0.080Mₓ3 = 0.240M. Because 1 mole of Al₂(SO₄)₃ contains 3 moles of SO₄²⁻.

<h3>Thus, the soluion that has the greatest [SO₄²⁻] is 0.080 M Al₂(SO₄)₃</h3>

8 0

3 years ago

What happens when wind sweeps up sand and throws it against a big rock?

RideAnS [48]

In deserts, wind often causes weathering by blowing sand and other material against cliffs and large rocks. This wears them down and creates more bits of sand and dust. Over time, the rock is scraped and polished away. ... When a gust of wind blows, it picks up sand and other bits of material.

4 0

3 years ago

Why did Thomson’s results from experimenting with cathode rays cause a big change in scientific thought about atoms?

IceJOKER [234]

Answer:

D, because he discovered electrons

Explanation:

8 0

3 years ago

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