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4 years ago

Is-7-2+5 the same as -7-(-2)+5

Mathematics

2 answers:

Harlamova29_29 [7]4 years ago

7 0

Answer:No

Step-by-step explanation:

ElenaW [278]4 years ago

3 0

Answer:

Step-by-step explanation:

1. -7 - 2 + 5: the minus between -7 and 2 and just saying it’s subtraction

2. -7 - (-2) + 5: the minus between -7 and (-2) is just saying “hey it’s subtraction but just a reminder the 2 is a negative too

So both equations will have different answers

1. -4

2. 0

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Write an equation for the line that passes through (- 3, 5) and is parallel to y = - 6x + 1.

soldier1979 [14.2K]

Answer:

y-5 = -6(x+3) OR y = -6x-13

Step-by-step explanation:

Let's use slope-intercept form to solve this problem.

Slope intercept form is the following:

y-y1 = m(x-x1)

x1 and y1 are given by the point in the problem.

x1 = -3, y1 = 5.

m is given by the equation in the problem. Lines that are parallel have the same slope. Thus,

m = -6.

If we plug these values into the equation for slope intercept form, we get the following:

y-5 = -6(x-(-3)) which becomes y-5 = -6(x+3)

This is an acceptable answer to the problem. However, point-slope form is also a way it can be written.

y-5 = -6x-18

y = -6x-13

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3 years ago

I got the answer it is A I just need you to check it pls thank you

andrey2020 [161]

We have a circle of radius 5 m inside a square of side 10 m. The shaded area is:

$A_{\text{Shaded}}=A_{\text{Square}}-A_{\text{Circle}}$

Now, we calculate the area of the square and the circle:

$\begin{gathered} A_{\text{Square}}=10^2=100m^2 \\ A_{\text{Circle}}=\pi\cdot5^2=25\pi m^2 \end{gathered}$

Finally, the shaded area is:

$A_{\text{Shaded}}=100-25\pi\approx21.5m^2$

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1 year ago

Gift tax falls under which tax category?

Liono4ka [1.6K]

Answer:

purchase tax!!

Step-by-step explanation:

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3 years ago

Read 2 more answers

Assignment

Ratling [72]

Answer:

8267

Step-by-step explanation

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3 years ago

Show that 5x^2 + 2x - 3 < 0 can be written in the form | x + 1/5 | < 4/5

Sliva [168]

Step-by-step explanation:

First let solve the inequality

$5 {x}^{2} + 2x - 3 < 0$

Factor by grouping

$5 {x}^{2} + 5x - 3x - 3 < 0$

$5x(x + 1) - 3(x + 1)$

So the factor are

$(5x - 3)(x + 1)$

So the factor are

$x = \frac{3}{5}$

and

$x = - 1$

Solutions to a quadratic can be represented by a absolute value equation because remeber quadratics

creates 2 roots and/or double roots.

The inequality

$|x - b| < c$

works as

b is the midpoint between 2 roots. And c is the

$|x + b| = c$

We know that the midpoint between both roots is-1/5.

$|x - ( - \frac{1}{5} )| < c$

$|x + \frac{1}{5} | < c$

Let use roots 3/5

$| \frac{3}{5} + \frac{1}{5} | = \frac{4}{5}$

-1 works as well.

$| - 1 + \frac{1}{5} | = | - \frac{4}{5} | = \frac{4}{5}$

So the absolute value equation is

$|x + \frac{1}{5} | < \frac{4}{5}$

8 0

3 years ago