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soldier1979 [14.2K]
3 years ago
8

Any help at all would be deeply appreciated. i am DESPERATE

Mathematics
1 answer:
Lana71 [14]3 years ago
6 0
The answers are C and D.
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How is multiplying exponents (x^2*x^4) different from raising a power to a power((x^2)^4)? Ty =)
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Answer:

When your multiplying exponents in the same parenthasis like x^2*x^4, you'll add the exponents so it will be x^6. If it is outside the parenthasis like (x^2)^4 you'll multiply the exponents so it will be x^8. good luck! :)

Step-by-step explanation:

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3 years ago
There are 57 people and i want everyone to have a slice of cake and i want to pay as little as possible and I want them to be th
julsineya [31]
So,

If you do some simple division, you will find how much each cm costs in each cake.
20cm cake = 67.5 cents/cm
25cm cake = 93.75 cents/cm

Assuming that you cannot order fractions of cakes, the best deal would be to order 5 of the 20cm cakes.
Cost = 13.50 * 5 = $67.50

You will have to pay $67.50 for the cakes if you want the best deal.
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3 years ago
Which expression represents the phrase “twice the quotient of 50 and a sum of a number y and 8
Alborosie

Answer:

2 * 50/(y + 8)

Step-by-step explanation:

"twice the quotient of 50 and a sum of a number y and 8"

y + 8

"twice the quotient of 50 and a sum of a number y and 8"

50/(y + 8)

"twice the quotient of 50 and a sum of a number y and 8"

2 * 50/(y + 8)

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H(x) = 2x2 + x + -3<br> Find h(2)
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7 the answer is 7 for this one
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2 years ago
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how to determine whether the equation defines y as a function of x. is it a function yes or no to the problem: x=y^2-6 and probl
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A\ function\ is\ a\ special\ relationship\ between\ values:\\\\ to\ each\ value\ of\ x\ the\ rule\ assigns\ one\ and\ only\ one\ value\ of\ y.\\------------------------------\\y=x^2+6\ \ \ it\ is\ the\ function\\\\x=0\ \ \ \Rightarrow\ \ \ y=0^2+6=6\\x=-3\ \ \ \Rightarrow\ \ \ y=(-3)^2+6=9+6=15\\x=5\ \ \ \Rightarrow\ \ \ y=5^2+6=25+6=31\\------------------------------\\x=y^2-6\ \ \ it\ is\ not\ the\ function\\

for\ example:\\x=3\ \ \ \ \Rightarrow\ \ \ \ 3=y^2-6\ \ \ \ \Rightarrow\ \ \ y^2=9\ \ \ \ \Rightarrow\ \ \ (y=3\ \ \ or\ \ \ y=-3)\\x=10\ \ \ \Rightarrow\ \ \ 10=y^2-6\ \ \ \Rightarrow\ \ \ y^2=16\ \ \ \Rightarrow\ \ \ (y=4\ \ \ or\ \ \ y=-4)\\x=75\ \ \ \Rightarrow\ \ \ 75=y^2-6\ \ \ \Rightarrow\ \ \ y^2=81\ \ \ \Rightarrow\ \ \ (y=9\ \ \ or\ \ \ y=-9)
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3 years ago
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