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3 years ago

The reactant Kl is an element an ionic compound a molecule an oxide

Chemistry

2 answers:

SashulF [63]3 years ago

4 0

Answer: an ionic compound

Explanation:

Murljashka [212]3 years ago

3 0

Answer : The reactant Kl is an ionic compound.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

Potassium iodide is an ionic compound because potassium element is a metal and iodide element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on potassium is (+1) and the the charge on iodide is (-1). Thus, the formula of the compound potassium iodide will be $KI$ .

Hence, the reactant Kl is an ionic compound.

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An aqueous solution was made by dissolving 72.9 grams of glucose, C6H12O6, into 115 grams of water. The vapor pressure of the pu

katen-ka-za [31]

Answer:

The correct answer is (d) 24.8 Torr

Explanation:

When a solute is added to a solvent, the water pressure of the solution is lower than the vapor pressure of the pure solvent. This is called <em>vapor pressure lowering</em> and it is given by the following expression:

Psolution= Xsolvent x Pºsolvent

We have to calculate Xsolvent (mole fraction of solvent) which is given by the number of moles of solute divided into the total number of moles.

First, we calculate the number of moles of solute and solvent. The solute is glucose (C₆H₁₂O₆), and its number of moles is calculated from the mass and the molecular weight (MM):

MM (C₆H₁₂O₆)= (12 g/mol x 6) + (1 g/mol x 12) + (16 g/mol x 6) = 180 g/mol

moles of glucose= mass/MM= (72.9 g)/)(180 g/mol)= 0.405 moles

The solvent is water (H₂O) and again we calculate the number of moles as follows:

MM(H₂O)= (1 g/mol x 2) + 16 g/mol = 18 g/mol

moles of water= mass/MM= (115 g)/(18 g/mol)= 6.389 moles

Now, we calculate the total number of moles (nt):

nt= moles of glucose + moles of water= 0.405 moles + 6.389 moles= 6.794 moles

The mole fraction of water (Xsolvent) is given by:

Xsolvent= moles of water/nt= 6.389 moles/6.794 moles= 0.940

Finally, the vapor pressure of water over the solution will be the following:

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3 years ago

Separate this redox reaction into its balanced component half‑reactions. Use the symbol e− for an electron. Cl2+2Li⟶2LiCl

ahrayia [7]

Answer:

Cl₂ ⟶ 2Cl⁻ + 2e⁻ Oxidation

2Li + 2e⁻ ⟶ 2Li⁺ Reduction

Explanation:

The question requests to split the equation below into half equations;

Cl2+2Li⟶2LiCl

In redox chemistry, splitting into half equations simply means highlighting the reduction and oxidation reactions of the reaction.

Before proceeding, we hav to split the ionic compound; LiCl into it's component ions. So we have;

Cl₂ + 2Li ⟶ 2Li⁺Cl⁻

This leaves us with;

Cl₂ ⟶ 2Cl⁻ ............................... i

2Li ⟶ 2Li⁺ .............................. ii

Oxidation reactions can be identified by the increase in oxidation number and decrease in the case of reduction.

in reaction i, there is a decrease in oxidation number from 0 to -1. This is the reduction half equation,

in reaction ii, there is an increase in oxidation number from 0 to +1. This is the oxidation half equation

In terms of electrons, we have to even the charge;

Oxidation = Loss of electrons

Reduction = Gain of electrons

The half equations are given as;

Cl₂ ⟶ 2Cl⁻ + 2e⁻ Oxidation

2Li + 2e⁻ ⟶ 2Li⁺ Reduction

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VashaNatasha [74]

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