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3 years ago

11

HURRY PLZ............. NEED HALPP!!!!!!!!!!!!!!!!!!

2 answers:

Nezavi [6.7K]3 years ago

6 0

The answer is D.At point 4, thermal energy from warm air over the land is transferred upward toward cooler areas of the atmosphere. Hope this helps :)

Alja [10]3 years ago

5 0

But where is the diagram

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A major computer chip manufacturer has lost its supplier of silicon. Silicon is widely used in the semiconductor industry becaus

-BARSIC- [3]

We know, silicon is a natural semi-conductor, if manufacturer has lost its supplier then they can look for another element which is quite similar to silicon in electronic configuration.
We should go down the group, next element in 14th group is "Germanium" so we can use that for that purpose.

In short, Your Answer would be "Germanium"

Hope this helps!

6 0

3 years ago

What does energy mean?

Fofino [41]

Answer:

strength and vitality required for sustained physical or mental activity

Explanation:

7 0

3 years ago

Read 2 more answers

Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.89×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.25×10−4, what is the

Sergio [31]

Answer:

$1.2\times 10^{-2}$

Explanation:

The given reactions are:

PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq) $K_3 = 1.89\times 10^{-10}$

AgCl(aq)⇌Ag+(aq)+Cl−(aq) $K_4 = 1.25\times 10^{-4}$

Required reaction is:

PbCl2(aq)+2Ag+(aq)⇌2AgCl(aq)+Pb2+(aq)

$K_f = \frac{K_3}{K_4^2}\\=\frac{1.89\times 10^{-10}}{1.25\times 10^{-4}}^2\\=1.2\times 10^{-2}$

4 0

4 years ago

What amount of energy is required to completely ionize 27.8 grams of carbon atoms in the gas phase (c(g)) if the ionization ener

zlopas [31]

I think it would be 2,510 kJ, or 2,510,000 J.

3 0

3 years ago

If only 0.186 g of Ca(OH)2 dissolves in enough water to give 0.230 L of aqueous solution at a given temperature, what is the Ksp

Lilit [14]

Answer:

$Ksp=5.20x10^{-6}$

Explanation:

Hello there!

In this case, according to the solubility equilibrium of calcium hydroxide:

$Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-$

Whereas the equilibrium expression is:

$Ksp=[Ca^{2+}][OH^-]^2$

It is firstly necessary to calculate the molar solubility given the grams and volume of the dissolved solute:

$s=\frac{0.186g/(74.09g/mol)}{0.230L}=0.0109M$

Now, according to the Ksp expression, we plug in s as the solubility to obtain:

$Ksp=(s)(2s)^2\\\\Ksp=(0.109)(2*0.0109)^2\\\\Ksp=5.20x10^{-6}$

Regards!

8 0

3 years ago