3 years ago

Define position and reference point in your own words. Dont copy and paste!

Chemistry

1 answer:

irga5000 [103]3 years ago

4 0

Answer: The beginning stage you decide to depict the area, or position, of an object.

Explanation: starting point or position

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What is the molarity of a solution that contains 25 g of HCl in 150 mL of solution??

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To find molarity
1) number of mol of solute.
Solute is HCl.
M(HCl)= 1.0+35.5 =36.5 g/mol

25g *1 mol/36.5 g = 25/36.5 mol HCl

2) Molarity is number of mole of the solute in 1 L solution.
150 mL = 0.150 L

(25/36.5 mol HCl )/(0.150 L) = 25/(36.5*0.150) ≈ 4.57≈4.6 mol/L

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Carry out the following calculation, paying special attention to the significant figures (where 4/3 is exact), rounding, and uni

babunello [35]

Answer:

Value = 1.80 g/cm³ (Approx)

Explanation:

Given:

$\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(1.65 \times 10^2 cm)^3}$

Computation:

$\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(1.65 \times 10^2 cm)^3} \\\\\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(4.492125 \times 10^6 cm^3)} \\\\ \frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(4.492125 \times 10^6 cm^3)}\\\\ \frac{3.39 \times 10^7g}{18.8166132\times 10^6 cm^3} \\\\ 1.80159945g/cm^3$

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3 years ago

You have 255 mL of a 1.5 M solution, how much liquid do you need to BOIL AWAY to increase the molarity to 2.5 M?

Lera25 [3.4K]

Answer:

102ml

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by using the dilution formulae and then you slove for the second volume by making it subject of the fomular
when you get it you then subtract the final volume that you got from the initial volume because they asked from the question what liquid do u need to boil away

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