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3 years ago

11

Catherine 168 pieces of gum playing at a bean bag toss in the county fair at school she gave three to every student in her math

class she has 8 remaining how many students are in her class

1 answer:

Drupady [299]3 years ago

7 0

Givens

Let the number of students in the class be x

Let the number of pieces of gum she gave out be 3x

Equation

3x + 8 = 168 This will not work out evenly. Let's try x - 1. The reason for that is because she may not give out anything to herself.

3(x - 1) + 8 = 168 This doesn't work either.

Well we have to choose. It's a rounding problem.

3x + 8 = 168 Subtract 8 from both sides.

3x = 168 - 8 Combine

3x = 160 Divide by 3 on both sides.

x = 160 / 3

x = 53.333333333

Since that can't be, we could say there were 53 students.

3x

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Answer:

a) x = -7

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The are a couple of rules you should know first.

Negative exponent rule: $a^{-x} = \frac{1}{a^{x}}$

A negative exponent means the same thing as the positive exponent as a denominator under 1.

Exponent to another exponent: $(a^{x})^{n}=a^{xn}$

When raising an exponent to another exponent, you multiply the exponents.

Fraction as a base rule: $(\frac{a}{b})^{x} = \frac{a^{x}}{b^{x}}$

Apply the exponent to the numerator and denominator.

Base 1 rule: $1^{x} = 1$

1 to the power of anything is 1.

Focus on exponents only: $a^{x} = a^{n}\\x = n$

If the bases are the same on both sides of the equation, you can solve for "x" in the exponent by focusing on it only.

Write as an exponent: Rewrite a normal number as an exponent instead. Example: $8=2^{3}$ or $125=5^{3}$

Also, you need to know how to rearrange and simplify formulas to isolate variables (by doing reverse operations in reverse BEDMAS order).

Know how to use the distributive property with brackets, when you multiply each of the terms in the brackets with the term on the outside.

Use each of these rules to solve.

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$x = -3-4$

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$5^{2x}=\frac{1}{5^{3}}$ Negative exponent rule

$5^{2x}=5^{-3}$ Focus only exponents only

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