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3 years ago

Once again a picture,, please help me with this one, thank you!!

Mathematics

2 answers:

Sati [7]3 years ago

7 0

Answer:

1395

Step-by-step explanation:

SA is the sum of all areas.

THe area of each side of the cube is 15^2 feet = 225 feet

There are 5 outwards facing sides of the cube so 225*5=1125

Each side of the triangle has an area of 1/2 *b*h, in this case, 1/2*15*9=67.5

THe triangle has four sides so 67.5*4=270

270+1125=1395

vazorg [7]3 years ago

5 0

Answer:

1395

Step-by-step explanation:

5 surfaces of the cuboid can be seen,so 5*l^2

4 surfaces of triangle = 4* 1/2 * 15 * 9

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G is proportional to the square of t. If t=2 and g=64, find g when t=3.5.

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$If\ g\ is\ proportional\ to\ the\ t^2\ we\ have\ proportion\\\\
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Dina and Masha start cycling on a 20 km bike path at the same time. When Dina reaches the end of the path, Masha still has 4 km

sammy [17]

Answer:

0.5 hour

Step-by-step explanation:

Given

Speed of Dina = 10 km/h

Distance = 20 km

So the time Dina taken to complete the track is:

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So we know the time and distance:

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Four lawn sprinkler heads are fed by a 1.9-cm-diameter pipe. The water comes out of the heads at an angle of 35° above the horiz

klemol [59]

Answer:

Step-by-step explanation:

Given:

Angle, θ = 35°

Vertical distance, Δx = 6 m

Diameter, d = 1.9 cm

= 0.019 m

When the water leaves the sprinkler, it does so at a projectile motion.

Therefore,

Using equation of motion,

(t × Vox) = 2Vo²(sin θ × cos θ)/g

= Δx = 2Vo²(sin 35 × cos 35)/g

Vo² = (6 × 9.8)/(2 × sin 35 × cos 35)

= 62.57

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Area of sprinkler, As = πD²/4

Diameter, D = 3 × 10^-3 m

As = π × (3 × 10^-3)²/4

= 7.069 × 10^-6 m²

V_ = volume rate of the sprinkler

= area, As × velocity, Vo

= (7.069 × 10^-6) × 7.91

= 5.59 × 10^-5 m³/s

Remember,

1 m³ = 1000 liters

= 5.59 × 10^-5 m³/s × 1000 liters/1 m³

= 5.59 × 10^-2 liters/s

= 0.0559 liters/s.

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The rate at which volume is flowing in the 4 sprinklers = 4 × 0.0559

= 0.224 liters/s

Area of 1.9 cm pipe, Ap = πD²/4

= π × (0.019)²/4

= 2.84 × 10^-4 m²

Volumetric flowrate of the four sprinklers = 4 × 5.59 × 10^-5 m³/s

= 2.24 × 10^-4 m³/s

Velocity of the water, Vw = volumetric flowrate/area

= 2.24 × 10^-4/2.84 × 10^-4

= 0.787 m/s

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