Answer:
With 95% confidence when n equals 44, the population mean is between a lower limit of 33.96 and an upper limit of 40.04
Step-by-step explanation:
Confidence Interval = mean + or - Error margin (E)
mean = 37
sd = 10
n = 44
degree of freedom = n - 1 = 44 - 1 = 43
t-value corresponding to 43 degrees of freedom and 95% confidence level is 2.0165
E = t × sd/√n = 2.0165×10/√44 = 3.04
Lower limit = mean - E = 37 - 3.04 = 33.96
Upper limit = mean + E = 37 + 3.04 = 40.04
95% confidence interval is between 33.96 and 40.04
Answer:
The answer is 8
Step-by-step explanation:
-5/2 x 8= 20 and if you add 5 it is 25.
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
10,100,1000,-10,-100,-1000
Step-by-step explanation:
Always.
So it is B.
Hope This Helps
