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Anna [14]
3 years ago
13

Kyle’s handful of trail mix has 2 almonds, 4 peanuts, 3 raisins, and 5 sunflower seeds. If he picks one item from the handful of

trail mix at random, what is the probability that the item is a peanut?
Mathematics
2 answers:
Natalka [10]3 years ago
8 0

Answer:

The probability is 2/7 or 28.57%

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

so

P=\frac{x}{y}

In this problem we have

x=4  ---> number of peanuts

y=2+4+3+5=14  ---> total number of items

substitute

P=\frac{4}{14}

Simplify

P=\frac{2}{7}=0.2857

Convert to percentage

0.2857*100=28.57\%

tresset_1 [31]3 years ago
6 0

Answer:

c

Step-by-step explanation:

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ethan made a rectangular prism that has a volume of 16 cubic inches. What is one set of possible dimensions for ethans rectangul
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Answer:

  0.5 inches by 0.5 inches by 64 inches

Step-by-step explanation:

Any three positive dimensions that have a product of 16 will be a set of possible dimensions. There are an infinite number of them. One such is listed above.

(If you have a list of answer choices, you can multiply them out to see which have a product of 16. We cannot guess what your choices might be.)

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3 years ago
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R=8 P=7 R+P= PLZ im stuck <br>​
mihalych1998 [28]

Answer:

15

Step-by-step explanation:

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R=8   P=7

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7 0
3 years ago
1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules
hoa [83]
<span>1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules

Formula: Heat = mass * specific heat * ΔT

Data:
mass = 50 g = 0.050 kg
specific heat of iron = 450 J/ kg °C
ΔT = 124°C - 10°C ¿ 114 °C

=> heat = 0.050kg * 450 J / kg°C * 114°C ≈ 2.6 J

2. If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the refrigerator if it released 492J of energy to the room? Joules

The firs law of thermodynamics is conservation of energy => energy removed from inside of the refrigerator = energy released to the room

=> Answer = 492 J

3. How much heat is needed to raise the temperature of 45g of water by 63oC? Joules

Formula: heat = mass * specific heat * ΔT

specific heat of water = 4186 J / Kg °C

heat = 0.045 kg * 4186 J/kg °C * 63°C = 11,867.31 J
</span>
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