The complete question in the attached figure
Part A) find the perimeter
[perimeter of the garden]=[perimeter square 1]+[perimeter a quarter circle]+[perimeter square 2]
[perimeter square 1]=5+5+5-----> 15 ft
[perimeter square 2]=5+5+5-----> 15 ft
[perimeter a quarter circle]=(2*pi*r)/4------> 2*pi*5/4-----> 7.85 ft
[perimeter of the garden]=[15]+[7.85]+[15]-------> 37.85 ft
the answer Part A) isthe perimeter of the garden is 37.85 ftPart B) Find the area of the garden
[Area of the garden]=[Area square 1]+[Area a quarter circle]+[Area square 2]
[Area square 1]=5*5-----> 25 ft²
[Area square 2]=5*5-----> 25 ft²
[Area a quarter circle]=(pi*r²)/4------> pi*5²/4-----> 19.625 ft²
[Area of the garden]=[25]+[19.625]+[25]-------> 69.625 ft²
the answer Part B) isthe Area of the garden is 69.625 ft²
Step-by-step explanation:
sin∅=-3/4 in 4 quadrant which sine is negative there
using soh cah toa
sin=opp/hyp
where our opp=-3 and our hyp=4
using pythagoras theorem
hyp²=opp²+adj²
(4)²=(-3)²+adj²
16=9+adj²
16-9=adj²
adj²=7
adj=√7
from soh cah toa
cos∅=adj/hyp
cos∅=√7/4
X-7=8
Add 7 to both sides so you can isolate the variable
x=15
Answer:
18
Step-by-step explanation:
Find the factors of each denominator
2 = 1*2
6 = 2*3
9 = 3*3
The least common multiple is
2*3*3 = 18
The least common denominator is 18
Y=(kx)/z
15=(k10)/4
15=(5k/2)
15=k(5/2)
ties both sides by 2/5 to clear fraction
6=k
y=(6x)/z
x=20
z=6
y=(6*20)/6
y=20