Step-by-step explanation:
1.) Plug in one of the points.
y = 8x + b
6 = 8(4) + b
2.) Solve for b (or [?])
32 cancels out on the right side.
Subtract 32 from 6, which is -26
3.) -26 = b
4.) Check with other point:
-2 = 8(3) + b
-2 = 24 + b
Cancel out 24 on the right side: 24-24 = 0
-2 - 24 = -26
-26 = b
Answer:
the answer for will be x≥-4
There are 5 solutions for this system.
x^2 + 4y^2 = 100 ____1
4y - x^2 = -20 ____2
Add both 1 & 2 together. x^2 gets cancelled
4y^2 + 4y = 80 (send 80 to the other side and divide by 4)
Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
Solve for y : y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
x^2 = 100 - 4y^2 x = /100 - 4y^2 (/ means square root) Replace values of y
y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
y = 4, x = /100 - 4(4)^2 = / 100 - 64 = /36 = -6 or 6
Thus we have 6 solutions y = -5, 4 and x = -6, 0, 6
Since 93p+84=85
subtract 84 from both sides
93p=1
p=(1/93)
