(2r)^5 typed in expanded form.

Cylinder has a height of 15 centimeters and a radius of 10 centimeters. What is its volume? Use ≈ 3.14 and round your answer t

tatuchka [14]

Answer: 4712.39 centimeters

Step-by-step explanation: Using the volume of a cylinder calculator, I got the answer of 4712.3889803847 centimeters, but rounded it to the nearest hundreth. Hope this helps!

3 0

3 years ago

I NEED HELP PLEASE, THANKS! :) Determine the zeros for and the end behavior of f(x) = x(x – 4)(x + 2)^4.

Amiraneli [1.4K]

Answer: a) zeros: x = {0, 4, -2}

b) as x → ∞, y → ∞

as x → -∞, y → ∞

Step-by-step explanation:

I think you mean (a) find the zeros and (b) describe the end behavior

(a) Find the zeros by setting each factor equal to zero and solving for x:

x (x - 4) (x + 2)⁴ = 0

x = 0 Multiplicity of 1 --> odd multiplicity so it crosses the x-axis

x = 4 Multiplicity of 1 --> odd multiplicity so it crosses the x-axis

x = -2 Multiplicity of 4 --> even multiplicity so it touches the x-axis

Degree = 6

(b) End behavior is determined by the following two criteria:

Sign of Leading Coefficient (Right side): Positive is ↑, Negative is ↓
Degree (Left side): Even is same direction as right side, Odd is opposite direction of right side

Sign of the leading coefficient is Positive so right side goes UP

as x → ∞, y → ∞

Degree of 6 is Even so Left side is the same direction as right (UP)

as x → -∞, y → ∞

7 0

4 years ago

What is the radius of a circle whose equation is x2+y2+8x−6y+21=0?

melamori03 [73]

Answer:

2 units

Step-by-step explanation:

none

8 0

3 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

$\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

3 years ago

Explain how to graph the inequality 8>Y

Colt1911 [192]

Answer:

go on the y-axis and find line 8. draw a line from one side of the graph to the other going through 8. then shade everything BELOW the line. #markasbrainliest

6 0

3 years ago