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3 years ago

7

A scientist is cooling a liquid at a steady rate. The temperature of the liquid changed by −8212 °C over 215 minutes. What was t

he temperature change after 1 minute?

2 answers:

solong [7]3 years ago

5 0

-8212/215 = 38.19 degrees.

kari74 [83]3 years ago

5 0

I think you meant 82 1/2 and 2 1/5 so according to those the answer is indeed -37.5 8) ;)

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A system has one each of two different types of components in joint operation. Let X and Y denote the random lengths of the live

RSB [31]

Answer:

The value of E(Y/X) is 2.

Step-by-step explanation:

As the complete question is not given, thus the complete question is found online and is attached herewith.

So the joint density function is given as

$f(x,y)=\left \{ {{\dfrac{x}{8}e^{-\dfrac{x+y}{2}} \,\,\,\,0 \leq x,0\leq y \atop {0}} \right.$

So the marginal function for X is given as

$f_x=\int\limits^{\infty}_0 {f(x,y)} \, dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x+y}{2} }dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x}{2}}e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{8}e^{-\frac{x}{2}}\int\limits^{\infty}_0e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{4}e^{-\frac{x}{2}}$

Now

$f(Y/X)=\dfrac{f(X,Y)}{f(X)}\\f(Y/X)=\dfrac{\dfrac{x}{8}e^{-\frac{x+y}{2} }}{\dfrac{x}{4}e^{-\frac{x}{2}}}\\f(Y/X)=\dfrac{1}{2}e^{-\frac{y}{2} }$

Now the value of E(Y/X) is given as

$E(Y/X)=\int\limits^{\infty}_0 {yf_{Y/X}} \, dy \\E(Y/X)=\int\limits^{\infty}_0 {y\dfrac{1}{2}e^{-\frac{y}{2} } }\, dy\\E(Y/X)=\dfrac{1}{2}\dfrac{\sqrt{2}}{(\dfrac{1}{2})^2}=2$

So the value of E(Y/X) is 2.

3 0

3 years ago

PLEASE HELP im dying over here

Iteru [2.4K]

$\dfrac{x}{24\sqrt{2}}=\cos45^\circ\\\\\\\dfrac{x}{24\sqrt{2}}=\dfrac{\sqrt{2}}{2}\qquad\qquad\qquad\text{(cross multiply)}\\\\\\2x=24\sqrt{2}\cdot\sqrt{2}\\\\2x=24\cdot2\quad|:2\\\\\boxed{x=24}$

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3 years ago

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2 years ago

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Harrizon [31]

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oksano4ka [1.4K]

Answer:

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Step-by-step explanation:

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