<span>The
content of any course depends on where you take it--- even two courses
with the title "real analysis" at different schools can cover different
material (or the same material, but at different levels of depth).
But yeah, generally speaking, "real analysis" and "advanced calculus"
are synonyms. Schools never offer courses with *both* names, and
whichever one they do offer, it is probably a class that covers the
subject matter of calculus, but in a way that emphasizes the logical
structure of the material (in particular, precise definitions and
proofs) over just doing calculation.
My impression is that "advanced calculus" is an "older" name for this
topic, and that "real analysis" is a somewhat "newer" name for the same
topic. At least, most textbooks currently written in this area seem to
have titles with "real analysis" in them, and titles including the
phrase "advanced calculus" are less common. (There are a number of
popular books with "advanced calculus" in the title, but all of the ones
I've seen or used are reprints/updates of books originally written
decades ago.)
There have been similar shifts in other course names. What is mostly
called "complex analysis" now in course titles and textbooks, used to be
called "function theory" (sometimes "analytic function theory" or
"complex function theory"), or "complex variables". You still see some
courses and textbooks with "variables" in the title, but like "advanced
calculus", it seems to be on the way out, and not on the way in. The
trend seems to be toward "complex analysis." hope it helps
</span>
The answer is 8x-1 I believe
<h3>
Answer: Choice C</h3>
P = 11/40 + 1/4 - 1/20
=========================================================
Explanation:
The formula we use is
P(A or B) = P(A) + P(B) - P(A and B)
In this case,
- P(A) = 22/80 = 11/40 = probability of picking someone from consumer education
- P(B) = 20/80 = 1/4 = probability of picking someone taking French
- P(A and B) = 4/80 = 1/20 = probability of picking someone taking both classes
So,
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 11/40 + 1/4 - 1/20
which is why choice C is the answer
----------------
Note: P(A and B) = 1/20 which is nonzero, so events A and B are not mutually exclusive.
Answer:
each student gets 2 bars and a quarter of one (2.25 or 2 1/4)
Step-by-step explanation:
C(t)=30t
Since 120/4= 30
That means it is $30 per ticket
If t represents the number of tickets bought and it’s $30 per ticket it’s 30t to find the total cost
