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Mice21 [21]
2 years ago
7

The two-way frequency table shows the results of a survey of a certain forest. Find the probability that a randomly chosen tree

will be a California redwood tree taller than 300 ft. Round to the nearest thousandth. Trees in Forest Height of 300 ft Over Under Totals California Redwood 25 280 305 Giant Sequoia 35 270 305 Totals 60 550 610.
A. 0.459

B. 0.082

C. 0.417

D. 0.041
Mathematics
2 answers:
REY [17]2 years ago
7 0
Just read the table! 

<span>From "the probability that a randomly chosen tree": </span>
<span>    ⇒ How many Trees? </span>
<span>Write the denominator. </span>

<span>From "will be a California redwood tree taller than 300 ft"" </span>
<span>    ⇒ How many California redwood tree taller than 300 ft? </span>
<span>Write the numerator. </span>

<span>Done.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
olga nikolaevna [1]2 years ago
4 0

Answer: the answer is D. 0.041


Step-by-step explanation:


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Answer: Yes they could.

Step-by-step explanation:

The two pairs of sides given are proportional: 3/7 : 9/21

The two triangles have the side:side ratio, meaning they are similar

Because they are similar, their hypotenuses <em>could</em> lie along the same line, not guaranteed, but possible.

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Please help me out please
natita [175]

Answer:

RC = 40

Step-by-step explanation:

Note that the circumcentre is equally distant from the triangle's 3 vertices.

That is : PC = RC = QC

Equate any pair and solve for x

Using RC = PC, then

5x - 15 = 3x + 7 ( subtract 3x from both sides )

2x - 15 = 7 ( add 15 to both sides )

2x = 22 ( divide both sides by 2 )

x = 11

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5 0
3 years ago
Simplify.
ASHA 777 [7]

Answer:

C

Step-by-step explanation:

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4 0
3 years ago
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
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