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podryga [215]
2 years ago
12

Why is this not in quadratic form? x^6+ 5x^4 + 6

Mathematics
1 answer:
Bas_tet [7]2 years ago
3 0

Answer and Step-by-step explanation:

Quadratic form has only the exponent of 2 and 1 in it. An example of it is as shown:

3x^2 + 4x - 12

Your expression isn't a quadratic since it has a 6 as the highest exponent, but it is a trinomial (an expression that has 3 terms).

<u><em>#teamtrees #PAW (Plant And Water)</em></u>

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What is the product?
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Answer:

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4 0
3 years ago
- 2a = - 20<br> What is the most simplest answer?
Evgesh-ka [11]

- 2a = - 20 | x (-)

2a = 20

a = 20 : 2

a = 10

6 0
2 years ago
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Rewrite the expression in the form 6^n 6^-6/6^-5
oee [108]

Answer:

6^-1

Step-by-step explanation:

6^-6 - (-5) = 6^(-6 + 5) = 6^(-1)

A lot of things are going on in this question. Notice how the 5 is handled. It starts off in the denominator as - 5 and when brought to the numerator it becomes -(-5) which makes it + 5.

The answer is then easy. It is 6^(-6 + 5) = 6^-1

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8 0
3 years ago
Claire Reagan and Anthony deliver newspapers in the neighborhoods clear deliver 79 papers a day Reagan delivers 2490 papers a mo
Nata [24]

Answer:

90,747

Step-by-step explanation:

Clair delivery=79 per day

Total delivery per year=79×365 days

=28,835

Reagan delivery=2490 per month

Total delivery per year=2490×12 months

=29,880

Anthony delivery= 616 per week

Total delivery per year =616×52 weeks

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Total delivery altogether in a year=28,835+29,880+32,032

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4 0
3 years ago
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If the 13th and 38th terms of an arithmetic sequence are -53 and -128,
love history [14]

9514 1404 393

Answer:

  -2018

Step-by-step explanation:

The n-th term is ...

  an = a1 +d(n -1)

So, the given terms are ...

  -53 = a1 +12d

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Subtracting the first from the second gives ...

  (a1 +37d) -(a1 +12d) = (-128) -(-53)

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The 668th term will be ...

  a668 = a1 +d(668 -1) = a1 +667d = (a1 +37d) +630d

  a668 = -128 +630(-3) = -128 -1890 . . . . substitute for a38

  a668 = -2018

7 0
2 years ago
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