For the 1 first problem you have to do additive inverse where the subtraction sign is and then combine all the z's and then combine the normal numbers and then put plus sign in between
Answer:
y = 5, -4
Step-by-step explanation:
To solve proportions you cross-multiply.

Now that we have 8 = y^2 - y - 12, we must make the entire trinomial equal to 0 by subtracting 8 from both sides.
y^2 - y - 20 = 0
Factor the trinomial.
(y - 5)(y + 4) = 0
Make both factors equal to 0 to solve for both values of y.
- y - 5 = 0 --> y = 5
- y + 4 = 0 --> y = -4
y = 5, -4
12•1
13•6
12/78 divide both numbers by 6 to simplify
Answer- 2/13
Put into slope intercept form, y=mx+b where m=slope
p=-2q+6
slope is -2
subsitute values for q and get values for p
q=0, p=6
(q,p)
(0,6)
(1,4)
p=q+4
slope is 1
subsitutte
q=0,p=4
(q,p)
(0,4)
(1,5)
below are the graphs