A point at (4,6) is reflected across the x-axis.What is the y-coordinate of the reflected point?
1 answer:
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First, we have to find x- and y-intercepts of given equation.
1. y-intercept is a point (0, y) so substitute x = 0 and calculate:
y-intercept = (0, -3)
2. x-intercept is a point (or points) (x, 0), so when we substitute y = 0 there will be:
x-intercept = (3, 0)
Now, when we have x- and y-intercepts, we can write an equation of a line (graph of the linear function) that passes through this two points:
Our linear equation is: y = x - 3
1. y-intercept is a point (0, y) so substitute x = 0 and calculate:
y-intercept = (0, -3)
2. x-intercept is a point (or points) (x, 0), so when we substitute y = 0 there will be:
x-intercept = (3, 0)
Now, when we have x- and y-intercepts, we can write an equation of a line (graph of the linear function) that passes through this two points:
Our linear equation is: y = x - 3