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Studentka2010 [4]
3 years ago
8

The output of an economic system​ Q, subject to two​ inputs, such as labor L and capital​ K, is often modeled by the​ Cobb-Dougl

as production function Q=cL^a K^b. When a+b=​1, the case is called constant returns to scale. Suppose Q=12,200​, a = 1/6​, b= 5/6​, and c=42. Find the rate of change of capital with respect to labor, dK/dL.
Mathematics
1 answer:
Anna35 [415]3 years ago
6 0

Answer:

Step-by-step explanation:

Given

Economic system Q is given by

Q=cL^aK^b

also a+b=1

if Q=12,200

a=\frac{1}{6}

b=\frac{5}{6}

c=42

substitute these values

12,200=42\times (L)^{\frac{1}{6}}K^{\frac{5}{6}}

(L)^{\frac{1}{6}}K^{\frac{5}{6}}=\frac{12,200}{42}

K^{\frac{5}{6}}=\frac{12,200}{42(L)^{\frac{1}{6}}}

K=(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^{5}}

differentiate w.r.t to L to get \frac{dK}{dL}

\frac{dK}{dL}=(\frac{12,200}{42})^{\frac{6}{5}}\times (-5)\times L^{-6}

\frac{dK}{dL}=-5(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^6}

\frac{dK}{dL}=-\frac{4515.466}{L^6}

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