By making use of properties of <em>quadratic</em> equations, we conclude that the <em>maximum</em> height of the rocket is 245 feet.
<h3>What is the maximum height of the rocket?</h3>
In this problem we must obtain the <em>maximum</em> height reached by the rocket and based on the <em>quadratic</em> equation described in the statement. There is an algebraic approach to get such information quickly. First, we modify the polynomial into an <em>implicit</em> form:
- 5 · t² + 70 · t - h = 0
Graphically speaking, <em>quadratic</em> equations are parabolae and, in particular, the <em>maximum</em> height of the rocket is part of the vertex of the parabola. Then, the discriminant of the quadratic equation is:
70² - 4 · (- 5) · (- h) = 0
4900 - 20 · h = 0
h = 245
By making use of properties of <em>quadratic</em> equations, we conclude that the <em>maximum</em> height of the rocket is 245 feet.
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Answer:
120 1 062 = × P . giving P = ÷ 120 1 062 . = 106 799
Solution: We have to find the Frequency and Relative frequency of the given data:
Frequency is the number of times a number occurs.
Relative Frequency is the number of times a number occurs divided by the total number of items.
Therefore, the frequency and relative frequency are calculated as below:
Number Frequency Relative Frequency
20 1 
21 4 
22 2 
23 4
24 3 
25 2 
26 3 
27 5 
28 3 
29 4 
Total 31
Answer:
The answer is Y + X as you just replace them.
Step-by-step explanation:
X + Y = Y + X
2 because it’s multiplied by 2 so it would go 2x2 = 4 x 2 = 8 and so on