Change 15/4 to mixed number

1 answer:

7 0

15/4

how many times does 4 go into 15 without going over.....that would be 3 times....so 3 is ur whole number. 3 * 4 = 12......15 - 12 = 3...and 3 is ur numerator....the denominator stays the same

so ur answer is : 3 3/4

You might be interested in

A positive number is A negative number is

marysya [2.9K]

Answer:

A positive number is the opposite of a negative number witch is negative

ex: 1,2,3,4,5,6,7,8,9

A negative number is the opposite of a positive number

ex: -1,-2,-3,-4,-5,-6,-7,-8,-9

6 0

3 years ago

Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans

zloy xaker [14]

Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the perimeters of the quadrilaterals the same is 2.

Part B:

The area of the square is given by

$Area=(x+4)^2=x^2+8x+16$

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

$x^2+8x+16=6x+8 \\ \\ \Rightarrow x^2+8x-6x+16-8=0 \\ \\ \Rightarrow x^2+2x+8=0 \\ \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2} \\ \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2} \\ \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}$

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.

7 0

3 years ago

What is the area of this trapezoid? 175 in² 140 in² 129 in² 85 in²

aksik [14]

Area of trapezoid = (B1 + B2)h/2

B1 = 15 in. + 4 in. + 6 in. = 25 in.
B2 = 15 in.
h = 7 in.

Area = (25 in. + 15 in.)(7 in.)/2 = 140 in.^2

3 0

3 years ago

Read 2 more answers

Which graph shows a non-proportional linear relationship between x and y?

andreev551 [17]

Answer: B

Because it does not pass through (0,0)