Answer:
Step-by-step explanation:
<u>Even function has following property:</u>
<u>It is easy to show this works with the second choice only. All the others don't work:</u>
- g(x) = (x - 1)² + 1
- g(-x) = (-x - 1)² + 1
This is not correct as x - 1 ≠ -x - 1 so as their squares, so g(x) ≠ g(-x)
The last two choices are not even similarly.
Answer:
144 = each interior angle
Step-by-step explanation:
The sum of the interior angles of a regular polygon is
(n – 2)180
If it is regular with n sides, divide by n to find each interior angle
(n – 2)180
------------------- = each interior angle
n
We know that there are 10 sides so n = 10
(10 – 2)180
------------------- = each interior angle
10
(8)180
------------------- = each interior angle
10
144 = each interior angle
Consider the given decagon of all equal sides.
Given: 
To find: 
Construction: Join a dotted line from point T to P.
Now,
and
lies on the straight line. Hence, they form linear pair.
Therefore, 


(equation 1)
Now, consider triangle TBP with two equal sides TB and BP.
By using the property
"Angles opposite to equal sides of an isosceles triangle are equal."
Since TB=BP, therefore the angles opposite to these sides are also equal.

From equation 1,

Now, in triangle TBP,
By using angle sum property, which states
" The sum of measures of all three angles of a triangle is 180 degrees"





So, the measure of angle TBP is 60 degrees.