Answer:
Magmatism is the emplacement of magma within and at the surface of the outer layers of a terrestrial planet, which solidifies as igneous rocks. ... On Earth, magma forms by partial melting of silicate rocks either in the mantle, continental or oceanic crust.
Explanation:
If the light of wavelength 700 nm strikes such a photocathode the maximum kinetic energy, in eV, of the emitted electrons is 0.558 eV.
so - $KE_{max} = hc/lembda} work
threshold when KE = 0
hc/lambda = work = 1240/900=1.38 eV
b) Kemax = hc/lambda - work = 1240/640 -1.38=0.558 eV
What is photocathode?
- A photocathode electrolyte interface can be used in a photoelectrolysis cell as the primary light-harvesting junction (in conjunction with an appropriate electrochemical anode) or as an optically complementary photoactive half-cell in a tandem photoelectrode photoelectrolysis cell (Hamnett, 1982; Kocha et al, 1994).
- In the case of the former, the electrode should ideally harvest photon energy across the majority of the solar spectrum in order to achieve the highest energy conversion efficiency possible.
- In the latter case, however, the photocathode may only be active in a specific band of the solar spectrum in order to generate a cathodic photocurrent sufficient to match the current generated in the photoanodic half-cell.
To learn more about Photocathode from the given link:
brainly.com/question/9861585
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From my new perspective, the new intensity of the
light source has decreased by a factor of four.
Answer:
swamp
Explanation:
I think. The desert is hot and less humid. Mountain is more cold. Tundra...no
Answer:
11250 N/C
Direction: 0 deg counterclockwise from positive x-axis
Explanation:
= magnitude of charge on each particle = 5 μC = 5 x 10⁻⁶ C
= distance of each particle from center of circle = 2 m
= Magnitude of electric field at the center by each particle
Magnitude of electric field at the center by each particle is given as
inserting the values
From the diagram , we see that being equal and opposite, the electric fields due to charge q₁ and q₃ cancel out.
So net electric field at center is only due to charge q₂ direction towards positive x-direction
So
= Resultant electric field = 11250 N/C
Direction: 0 deg counterclockwise from positive x-axis
