Answer:
The voltage drop across the bulb is 115 V
Explanation:
The voltage drop equation is given by:
Where:
ΔW is the total work done (4.6kJ)
Δq is the total charge
We need to use the definition of electric current to find Δq
Where:
I is the current (2 A)
Δt is the time (20 s)
Then, we can put this value of charge in the voltage equation.
Therefore, the voltage drop across the bulb is 115 V.
I hope it helps you!
Answer:
3ohms
Explanation:
From Ohm's Law
V = IR
V is that voltage = 3volts
I = current = 1amp
R = resistance in ohms
Putting those values into the above formula.
3volts = 1amp×R
Making R the subject
R = 3/1
R = 3ohms
The resistance of the light bulb is 3ohms.
Answer:
The maximum speed is 21.39 m/s.
Explanation:
Given;
radius of the flat curve, r₁ = 150 m
maximum speed, 
= 32.5 m/s
The maximum acceleration on the unbanked curve is calculated as;
the radius of the second flat curve, r₂ = 65.0 m
the maximum speed this unbanked curve should be rated is calculated as;
Therefore, the maximum speed is 21.39 m/s.
