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neonofarm [45]
2 years ago
6

Someone who understands? Please Hély me

Mathematics
1 answer:
Dahasolnce [82]2 years ago
8 0
Slope/-2/2 y-inetercept/1
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Simplify X^2+6-27/x-3
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(x + 9)

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3 years ago
Drive to work in 45 min., bus to work takes 1 hr 15 min. If the average rate on the bus is 16 mph slower than his driving rate,
stich3 [128]

Answer:

30 miles

Step-by-step explanation:

Given: Drive to work in 45 min.

           Bus would take to travel= 1 hr 15 min

          Average rate on the bus is 16 mph slower than his driving rate.

Lets assume the average driving rate be "x" mph.

∴ Average rate of bus= (x-16)\ mph

Now converting unit of time taken to travel to work.

Remember; 1 hours= 60 minutes.

Time taken for drive to work= \frac{45\ minutes}{60\ minutes} = 0.75\ hour

Time taken in bus to work= 1 hour and 15 minutes=60\ minutes+ 15\ minutes= 75\ minutes

∴ Time taken in bus to work in hours= \frac{75\ minutes}{60\ minutes}= 1.25\ hours

Considering the distance remain constant to travel for work.

Next, forming an equation to find the value of x.

As we know, distance= speed\times time

⇒ x\times 0.75= (x-16)\times 1.25

Using distributive property of multiplication.

⇒0.75x= 1.25x-20

Adding both side by 20

⇒ 0.75x+20= 1.25x

Subtracting both side by 0.75x

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Dividing both side by 0.5

⇒x= \frac{20}{0.5}

∴ x= 40\ mph

Hence the average rate for drive to work is 40mph.

Now, subtitiuting the value of x to find the distance travelled to work.

Distance travelled= 40\times 0.75= 30\ miles

Hence, distance travelled to work is 30 miles.

6 0
3 years ago
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