<em> </em><em>Ans</em><em> </em><em>is</em><em> </em><em>in</em><em> </em><em>attached</em><em> </em><em>picture</em><em>.</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em> </em><em>hai</em><em>.</em><em> </em><em> </em><em>dai</em><em>.</em><em>.</em><em>.</em><em>.</em>
we know that
<u>Applying the Pythagorean Theorem</u>

solve for HJ

in this problem we have

Substitute the values in the formula above




therefore
<u>the answer is the option</u>
B. 5 sq. root 3 units
The first square is 100% and the second square is 55% filled in
The original price is $ 60
<em><u>Solution:</u></em>
Given information are:
Original price = ?
Percent of discount = 5 %
Sales price = $ 57
So, we have to find out the original price
Let "x" be the original price
Then, we can say,
Original price = sales price + discount percent of original price
x = 57 + 5 % of x

Thus original price is $ 60
Answer:
Exactly one solution.
Step-by-step explanation:
2x-4y=8
x+2y=4 /*2
<em>2x-4y=8</em>
<em><u>2x+4y=8 (+)</u></em>
4x=16
x=4
4+2y=4
y=0
(x;y)={(4; 0)}
Exactly one solution.