Answer:
The amount that would be in the account after 30 years is $368,353
Step-by-step explanation:
Here, we want to calculate the amount that will be present in the account after 30 years if the interest is compounded yearly
We proceed to use the formula below;
A = [P(1 + r)^t-1]/r
From the question;
P is the amount deposited yearly which is $4,500
r is the interest rate = 2.5% = 2.5/100 = 0.025
t is the number of years which is 30
Substituting these values into the equation, we have;
A = [4500(1 + 0.025)^30-1]/0.025
A = [4500(1.025)^29]/0.025
A = 368,353.3309607034
To the nearest whole dollars, this is;
$368,353
Answer: Graph B
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Explanation:
Point A appears to be at (2.5, -1)
If we shift 6 units to the left, then we subtract 6 from the x coordinate. So the new x coordinate is now 2.5-6 = -3.5
If we shift 4 units up, then we add 4 to the y coordinate to go from -1 to -1+4 = 3
Overall, the point A(2.5, -1) moves to A'(-3.5, 3)
Graph B is the answer because of this. The other points B and C will follow the same pattern as point A does.
The answer for "-2a + 3b" is 5.
To solve this equation, you must first find "a" and "b". A^3 times B^2 = 72. In this case, a = 2 (2*2*2 = 8) and b = 3 (3*3 = 9) since their outcomes multiplied together equal 72.
Now you fill in for "a" and "b". "-2*2 + 3*3" before adding you do all the multiplying, which leaves "-4 + 9". Combining like terms gives you 5.
I hope this helps!!
Answer:
D.
Step-by-step explanation:
115x + 170 = 630
Subtract 170 from each side of the equals,
115x = 460
Divide 460 by 115,
4
Thus, D is your correct answer.
<em>Answered by:</em>
matthewarvin06
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