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2 years ago

State whether the triangles can be proven congruent, if possible, by AAS or ASA

Mathematics

1 answer:

dezoksy [38]2 years ago

8 0

Yup the answer is aas ^^

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The square of g is the same as two times the difference of g and 10. Write an expression.

tatuchka [14]

$g^2=2(g-10)$

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3 years ago

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Grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height. how high

bezimeni [28]

Given that grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height.

So if D is the diameter and h is the height of the conical pile then we can write:

D=3h

We know that diameter = 2r, where r is the radius

2r=3h

$r=\frac{3h}{2}$

Volume of conical pile is given by formula

$V=\frac{1}{3}\pi r^2h$

Given that volume is 1110 cubic feet.

Now plug the values of Volume and r into equation of volume

$1110=\frac{1}{3}\pi (\frac{3h}{2})^2h$

$1110=\frac{1}{3}\pi\cdot\frac{9h^2}{4}\cdot h$

$1110=\pi\cdot\frac{3h^3}{4}$

$1110\cdot\frac{4}{3\pi}=h^3$

$471.098631552=h^3$

take cube root of both sides

7.78103342467=h

Hence height is approx 7.78 feet.

7 0

3 years ago

10 points someone help me please!?

Soloha48 [4]

Answer:

$\large\boxed{b=\sqrt{95}}$

Step-by-step explanation:

Use the Pyhagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=b,\ leg=7,\ hypotenuse=12$

Substitute:

$b^2+7^2=12^2$

$b^2+49=144$ <em>subtract 49 from both sides</em>

$b^2=95\to b=\sqrt{95}$

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2 years ago

how many cubic blocks of side length 1/6 inch would take to fill a rectangular prism with a length, width, and height of 1/3 inc

borishaifa [10]

Volume of one cubic block = (1/6)^3 = 1/216 cu ins

Volume of the prism = 1/3 * 2/3 * 2/3 = 4/27 cu ins

Number of blocks to fill prism = 4/27 / 1/216 = (216*4) / 27 = 32

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2 years ago

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If the area around the vegetable garden is of uniform width (labeled with x) and the dimensions of the vegetable garden is 45 fe

Nady [450]

Area of Rectangle = Width × Length

Vegetable Garden
Width = 20
Length = 45
Area of Vegetable Garden = 20×45=900 Sq ft

Area of Entire Garden = Width × Length
Width = 20 + 2x
Length = 45 + 2x
Area = (20 + 2x)(45 + 2x)
(2x + 20)(2x + 45)
4x^2 + 90x + 45x + 900
Area of Entire Garden = 4x^2 + 135x + 900

Area of Flower Garden = Area of Entire Garden - Area of Vegetable Garden

(4x^2 + 135x + 900) - (20 × 45)
4x^2 + 135x + 900 - 900
Area of Flower Garden = 4x^2 + 135x

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2 years ago

State whether the triangles can be proven congruent, if possible, by AAS or ASA​

State whether the triangles can be proven congruent, if possible, by AAS or ASA