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Tasya [4]
2 years ago
10

How many real and complex roots exists for a polynomial?

Mathematics
1 answer:
solmaris [256]2 years ago
7 0

Step-by-step explanation:

whenever a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial. as an example, we'll find the roots of the polynomial..

x^5 - x^4 + x^3 - x^2 - 12x + 12.

the fifth-degree polynomial does indeed have five roots; three real, and two complex.

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Part 1

Add up the values in the table: 90+36+54+45+63+72 = 360

This means 360 total drinks were sold. Of that total, 54 were medium regular.

The percentage of medium regular is 54/360 = 0.15 = 15%

Apply this percentage to the 640 customers he plans to sell to

15% of 640 = 0.15*640 = 96

<h3>Answer: 96</h3>

============================================

Part 2

It sounds like your teacher wants you to find the probability of picking pink lemonade. The table says that 36 small, 45 medium, and 72 large pink lemonades were sold. That means 36+45+72 = 153 pink lemonades were sold out of the 360 total

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Then go through each answer choice to note that 17/40 = 0.425 as well

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Answer: 17/40

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